Firebase 云功能使用存储公共 URL 更新文档

发布于 2025-01-10 22:50:16 字数 1226 浏览 0 评论 0原文

前端应用程序正在 firestorm 中使用以下模型创建文档

fileRef 是字符串：“gs://bucket-location/folder/fileName.extention”

创建后，我想获取文件的公共 URL 并使用该 URL 更新文档

import * as functions from "firebase-functions";
import * as admin from "firebase-admin";
const firebase = admin.initializeApp();

interface DocumentDataType {
  fileRef: string; 
  fileType: "image" | "video";
  fileUrl: string;
  timestamp: FirebaseFirestore.Timestamp;
  location: FirebaseFirestore.GeoPoint;
}

exports.onDocumentCreated = functions.firestore
  .document("db/{docId}")
  .onCreate((snapshot, context) => {
    const bucket = firebase.storage().bucket();
    const { fileRef } = <DocumentDataType>snapshot.data();
    const file = bucket.file(fileRef);
    const fileUrl = file.publicUrl();
    const batch = admin.firestore().batch();
    batch.update(snapshot.ref, { ...snapshot.data(), fileUrl });
  });

函数被触发，但文件 URL 不更新。

这是将文件存储到云存储中的正确方法吗？ -
SDK v9 更新是否批量更新？我真的很困惑阅读文档，找不到合适的解决方案。

原文

A frontend application is creating documents in firestorm with following model

fileRef is string : "gs://bucket-location/folder/fileName.extention"

Now after creation I want to get the public URL of the file and update the document with the URL

import * as functions from "firebase-functions";
import * as admin from "firebase-admin";
const firebase = admin.initializeApp();

interface DocumentDataType {
  fileRef: string; 
  fileType: "image" | "video";
  fileUrl: string;
  timestamp: FirebaseFirestore.Timestamp;
  location: FirebaseFirestore.GeoPoint;
}

exports.onDocumentCreated = functions.firestore
  .document("db/{docId}")
  .onCreate((snapshot, context) => {
    const bucket = firebase.storage().bucket();
    const { fileRef } = <DocumentDataType>snapshot.data();
    const file = bucket.file(fileRef);
    const fileUrl = file.publicUrl();
    const batch = admin.firestore().batch();
    batch.update(snapshot.ref, { ...snapshot.data(), fileUrl });
  });

The functions get triggered but the file URL does not update.

is it the right approach for getting the file in cloud storage? -
and also does SDK v9 update is with batch? I really got confused reading the documentation and could not find a proper solution.

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神经大条 2025-01-17 22:50:16

当您尝试添加/更新/删除多个文档并希望确保所有操作通过或失败时，批量写入非常有用。在提供的代码中，您没有提交批次。使用 commit() 应该更新文档：

batch.commit().then(() => console.log("Document updated"));

但是，如果您只想更新单个文档，那么我更喜欢 update() ：

exports.onDocumentCreated = functions.firestore
  .document("db/{docId}")
  .onCreate(async (snapshot, context) => {
    const bucket = firebase.storage().bucket();
    const { fileRef } = <DocumentDataType>snapshot.data();
    const file = bucket.file(fileRef);
    const fileUrl = file.publicUrl();
    
    return snapshot.ref.update({ ...snapshot.data(), fileUrl });
  });

Batched writes are useful when you are trying to add/update/delete multiple documents and want to ensure all the operations either pass or fail. In the provided code you are not commiting the batch. Using commit() should update the document:

batch.commit().then(() => console.log("Document updated"));

However if you just want to update a single document then I would prefer update() instead:

exports.onDocumentCreated = functions.firestore
  .document("db/{docId}")
  .onCreate(async (snapshot, context) => {
    const bucket = firebase.storage().bucket();
    const { fileRef } = <DocumentDataType>snapshot.data();
    const file = bucket.file(fileRef);
    const fileUrl = file.publicUrl();
    
    return snapshot.ref.update({ ...snapshot.data(), fileUrl });
  });

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