正则表达式（排除）
我正在开发一个正则表达式函数来验证电子邮件地址是否有效。一切似乎都有效，但此电子邮件地址“[email protected]”应该返回条件中为“false”，因为它包含下划线。以下是我编写的代码。有没有办法可以从搜索中排除下划线（_）？
import re
def emailCheck(email):
result = re.search(r'((A-Za-z0-9.[_])*)@((\d?[a-z]?[A-Z]?)*(\b.com\b|\b.edu\b|\b.org\b))', email)
return bool(result)
I am working on a regex function that verifies if the email address is valid. All seem to work but this email address "[email protected]" should return 'false' in the condition because it contains underscore. The following is the code that I have written. Is there a way I could exclude underscore(_) from my search?
import re
def emailCheck(email):
result = re.search(r'((A-Za-z0-9.[_])*)@((\d?[a-z]?[A-Z]?)*(\b.com\b|\b.edu\b|\b.org\b))', email)
return bool(result)
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评论（1）
您的问题是
(A-Za-z0-9.[_])*。这只是任意字符A、Z、a、z、0< 的可选列表/code>、9、-和_。您需要一个范围字符类。它应该是
[A-Za-z0-9.]+并添加开始/结束行元转义。https://regex101.com/r/1Ors2C/1
Your issue is
(A-Za-z0-9.[_])*. This is just a optional listing of arbitrary charactersA,Z,a,z,0,9,-, and_.You need a character class for ranges. It should be
[A-Za-z0-9.]+and add a start/end line meta escape.https://regex101.com/r/1Ors2C/1