看一下十进制字段，作为 int 的数字 1 对应于现实生活中很少见到的不可打印字符。字符“1”对应49。
解：
switch(diff){
case '1': //notice the quotations
//rest of code
break;
}
Because of type mismatch! you defined "diff" as a char and use it as such in your switch statement. However, in your second switch statement, you remove the quotes and use it as a number. That causes a char to int conversion according to the ascii table.
Look at the decimal field, the number 1 as an int corresponds to a non-printable character that you will rarely see in real life. The character '1' corresponds to 49.
Solution:
switch(diff){
case '1': //notice the quotations
//rest of code
break;
}
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因为类型不匹配！
您将“diff”定义为字符并在 switch 语句中使用它。但是，在第二个 switch 语句中，您删除了引号并将其用作数字。这会导致根据 ascii 表进行 char 到 int 的转换。
看一下十进制字段，作为 int 的数字 1 对应于现实生活中很少见到的不可打印字符。字符“1”对应49。
解：
Because of type mismatch!
you defined "diff" as a char and use it as such in your switch statement. However, in your second switch statement, you remove the quotes and use it as a number. That causes a char to int conversion according to the ascii table.
Look at the decimal field, the number 1 as an int corresponds to a non-printable character that you will rarely see in real life. The character '1' corresponds to 49.
Solution:
对于这一行，
您的意思是
考虑到 diff 是键入的 char 而不是 int
for this line
you mean
given that diff is a typed in char not an int