打印嵌套列表中的某些元素

Question

我有一个函数，它可以打印低值和高值之间的运行时间总计。我创建了一个 powerset 函数并在我的新运行时函数中使用它。

在那些介于低和高之间的新集合中，我需要打印电影的名称。我在打印所有标题时遇到问题。我尝试过使用相同的 for 循环，但我无法弄清楚。所以，我保留了 i。

def show_marathon_options(movies, low, high):
    sets = power_set(movies)
    count = 1
    for i in sets:
        runtime = 0
        for j in i:
            runtime += j[1]
        if low <= runtime <= high:
            print(f'{count}. Total runtime for {i}: {runtime} mins.')
            count += 1

输入：

movie_20 = [['Back to the Future', 116], ['How to Train Your Dragon', 98], ['The Land Before Time', 69],
                ['The Lord of the Rings: The Return of the King', 201], ['Tangled', 100], ['Titanic', 194],
                ['The Godfather', 202], ['Schindler''s List', 195], ['The Green Mile', 189],
                ['Fanny and Alexander', 188], ['Avengers: Endgame', 181], ['The Wolf of Wall Street', 180],
                ['Casino', 178], ['Braveheart', 178], ['Interstellar', 169], ['Django Unchained', 165],
                ['Saving Private Ryan', 169], ['Logan', 137], ['Tarzan', 88], ['Mulan', 88]]

输出：

1. Total runtime for [['Back to the Future', 116], ['How to Train Your Dragon', 98]]: 214 mins.
2. Total runtime for [['Back to the Future', 116], ['The Land Before Time', 69]]: 185 mins.
3. Total runtime for [['Back to the Future', 116], ['How to Train Your Dragon', 98], ['The Land Before Time', 69]]: 283 mins.
4. Total runtime for [['The Lord of the Rings: The Return of the King', 201]]: 201 mins.
5......

需要格式输出：

1. Total runtime for Back to the Future, How to Train Your Dragon: 214 mins.
2. Total runtime for Back to the Future, The Land Before Time: 185 mins.
3. Total runtime for Back to the Future, How to Train Your Dragon, The Land Before Time: 283 mins.
4. Total runtime for The Lord of the Rings: The Return of the King': 201 mins.
5....

我尝试过 j[0]，但它只访问每行的第一个标题。

Answer 1

尝试使用 ', '.join(movie[0] for movie in i)，而不仅仅是 print() 语句中的 i。您需要迭代 i 的元素。