Groovy 从字符串创建 2 个暗淡数组 [][]

发布于 2025-01-10 10:57:15 字数 444 浏览 0 评论 0原文

string = """
name:bla1-service,
  version:Sprint-91.0.0
  
  name:bla2-service,
  version:Sprint-93.0.0
  
  name:cbla3-service,
  version:Sprint-93.0.0
  
  name:bla4-service,
  version:Sprint-93.0.0
  
"""

最终结果应该是一个数组，

myArray = [[bla1-service,version:Sprint-91.0.0],[bla2-service,Sprint-93.0.0] ...]

我可以使用 for 循环来搜索“名称”和“版本”等字符串并构建它，但我认为必须有一种更简单的方法（也许使用 split(",")？）谁能提出更好的方法？

原文

string = """
name:bla1-service,
  version:Sprint-91.0.0
  
  name:bla2-service,
  version:Sprint-93.0.0
  
  name:cbla3-service,
  version:Sprint-93.0.0
  
  name:bla4-service,
  version:Sprint-93.0.0
  
"""

end result should be an array

myArray = [[bla1-service,version:Sprint-91.0.0],[bla2-service,Sprint-93.0.0] ...]

i can use a for loop to search for string like "name" and "version" and build this but i figure there must be a simpler way (maybe using split(",")?)
can anyone suggest a better way?

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ㄟ。诗瑗 2025-01-17 10:57:15

正则表达式的一些简单的东西：

String string = """
name:bla1-service,
  version:Sprint-91.0.0
  
  name:bla2-service,
  version:Sprint-93.0.0
  
  name:cbla3-service,
  version:Sprint-93.0.0
  
  name:bla4-service,
  version:Sprint-93.0.0
  
"""

def res = []
string.eachMatch( /name:([^,]+),\s+version:(\S+)/ ){ _, name, version -> res << [ name, version ] }

assert res.toString() == '[[bla1-service, Sprint-91.0.0], [bla2-service, Sprint-93.0.0], [cbla3-service, Sprint-93.0.0], [bla4-service, Sprint-93.0.0]]'

Something straight-forward with regex:

String string = """
name:bla1-service,
  version:Sprint-91.0.0
  
  name:bla2-service,
  version:Sprint-93.0.0
  
  name:cbla3-service,
  version:Sprint-93.0.0
  
  name:bla4-service,
  version:Sprint-93.0.0
  
"""

def res = []
string.eachMatch( /name:([^,]+),\s+version:(\S+)/ ){ _, name, version -> res << [ name, version ] }

assert res.toString() == '[[bla1-service, Sprint-91.0.0], [bla2-service, Sprint-93.0.0], [cbla3-service, Sprint-93.0.0], [bla4-service, Sprint-93.0.0]]'

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