如何计算 C++ 中 C_String 中的字符数？

发布于 2025-01-10 10:40:55 字数 699 浏览 1 评论 0原文

我是一名计算机科学专业的新生，我有一个家庭作业问题如下：

编写一个函数，传入 C 字符串并使用指针确定字符串中的字符数。

这是我的代码：

#include <iostream>
#include <string.h>
using namespace std;
const int SIZE = 40;

int function(const char* , int, int);

int main()
{
     char thing[SIZE];
     int chars = 0;

     cout << "enter string. max " << SIZE - 1 << " characters" << endl;
     cin.getline(thing, SIZE);
     int y = function(thing, chars, SIZE);
     cout << y;
}


int function(const char *ptr, int a, int b){
    a = 0;
    for (int i = 0; i < b; i++){
        while (*ptr != '\0'){
            a++;
        }
    }
    return a;
}

原文

I'm a new Computer Science student, and I have a homework question that is as follows:

Write a Function that passes in a C-String and using a pointer determine the number of chars in the string.

Here is my code:

#include <iostream>
#include <string.h>
using namespace std;
const int SIZE = 40;

int function(const char* , int, int);

int main()
{
     char thing[SIZE];
     int chars = 0;

     cout << "enter string. max " << SIZE - 1 << " characters" << endl;
     cin.getline(thing, SIZE);
     int y = function(thing, chars, SIZE);
     cout << y;
}


int function(const char *ptr, int a, int b){
    a = 0;
    for (int i = 0; i < b; i++){
        while (*ptr != '\0'){
            a++;
        }
    }
    return a;
}

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極樂鬼 2025-01-17 10:40:55

我认为您正在尝试在这里重写 strlen() 函数。尝试查看以下链接查找 a 的大小指针指向的字符串。
简而言之，您可以使用 strlen() 函数来查找字符串的长度。您的函数的代码将如下所示：

int function(const char *ptr) 
{
    size_t length = strlen(ptr);
    return length;
}

您还应该只需要此函数和 main。

编辑：也许我误解了你的问题，毕竟你应该重新发明 strlen() 。在这种情况下，您可以这样做：

unsigned int my_strlen(const char *p)
{
    unsigned int count = 0;

    while(*p != '\0') 
    {
        count++;
        p++;
    }
    return count;
}

这里我将 *p 与 '\0' 进行比较，因为 '\0' 是空终止符。

这是取自 https://overiq.com/c -programming-101/the-strlen-function-in-c/

I think you are trying to rewrite the strlen() function here. Try giving the following link a look Find the size of a string pointed by a pointer.
The short answer is that you can use the strlen() function to find the length of your string. The code for your function will look something like this:

int function(const char *ptr) 
{
    size_t length = strlen(ptr);
    return length;
}

You should also only need this function and main.

Edit: Maybe I misunderstood your question and you are supposed to reinvent strlen() after all. In that case, you can do it like so:

unsigned int my_strlen(const char *p)
{
    unsigned int count = 0;

    while(*p != '\0') 
    {
        count++;
        p++;
    }
    return count;
}

Here I am comparing *p from '\0' as '\0' is the null termination character.

This was taken from https://overiq.com/c-programming-101/the-strlen-function-in-c/

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