设置差异并丢弃顺序
我有以下集合：
>>> s2 = set(((1,3),(2,3,6,4)))
>>> s1 = set(((1,3),(2,3,4,6)))
>>> s1.symmetric_difference(s2)
{(2, 3, 4, 6), (2, 3, 6, 4)}
我想比较上面的两个集合，但设置丢弃它们的顺序，这意味着它返回空集，例如：
>>> s1.symmetric_difference(s2)
set()
更新：
事实上，当两个集合的序列不同时，我想集合假设它们是一组。 我如何用Python中的集合来定义它？
I have the following sets:
>>> s2 = set(((1,3),(2,3,6,4)))
>>> s1 = set(((1,3),(2,3,4,6)))
>>> s1.symmetric_difference(s2)
{(2, 3, 4, 6), (2, 3, 6, 4)}
I want to compare two above sets but set discards order of them, It means It return null set such as:
>>> s1.symmetric_difference(s2)
set()
UPDATE:
Indeed when sequence of two sets are difference, I want to sets supposes they are one set.
How can I define it with sets in python?
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将集合存储为集合而不是元组。由于您需要它们可散列，因此请使用冻结集。就像
frozenset((1,3))而不是(1,3)一样。顺便说一句，您还可以使用
s1 ^ s2获得对称差。Store your sets not as tuples but as sets. Since you need them hashable, use frozensets. Like
frozenset((1,3))instead of(1,3).Btw you can also get the symmetric difference with
s1 ^ s2.使顺序无关的一种方法是使其相同。您可以在将元组放入集合之前对其进行排序：
One way to make order irrelevant is to make it the same. You could sort the tuples prior to putting them in a set: