Python代码打开json文件-更优化

发布于 2025-01-10 04:20:36 字数 464 浏览 0 评论 0原文

我怎样才能把这段代码写得更优化，而不是重复呢？所以，首先我检查是否有 .json 文件，如果没有，我就创建它。如果有，我首先打开它，用新数据更新它，然后再次写入。

    if not os.path.exists(json_path):
        with open(json_path, "w") as json_file:
            json.dump(my_dict, json_file)
    else:
        with open(json_path) as json_file:
            data = json.load(json_file)
            data.update(my_dict)
            with open(json_path, 'w') as json__file:
                json.dump(data, json__file)

原文

How could I write this piece of code more optimal, not to have repetition? So, first I'm checking if there's a .json file, if there isn't I make it. If there is, I first open it, update it with new data, and then write in it again.

    if not os.path.exists(json_path):
        with open(json_path, "w") as json_file:
            json.dump(my_dict, json_file)
    else:
        with open(json_path) as json_file:
            data = json.load(json_file)
            data.update(my_dict)
            with open(json_path, 'w') as json__file:
                json.dump(data, json__file)

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禾厶谷欠 2025-01-17 04:20:36

我认为你可以反转你的条件来先读取文件。然后稍后写入文件，因为你总是最终会写入。

if os.path.exists(json_path):
    with open(json_path) as json_file:
        data = json.load(json_file)
    data.update(my_dict)
    my_dict = data

with open(json_path, "w") as json_file:
    json.dump(my_dict, json_file)

I think you can invert your condition to read the file first. Then later write to the file because you always end up writing.

if os.path.exists(json_path):
    with open(json_path) as json_file:
        data = json.load(json_file)
    data.update(my_dict)
    my_dict = data

with open(json_path, "w") as json_file:
    json.dump(my_dict, json_file)

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