Askopenfile() 获得参数“模式”的多个值；在Python中

Question

我正在用 python 编写一个 python 程序，它要求我使用打开的对话框，

但我收到以下错误

Askopenfile() 获得了参数“模式”的多个值

我的代码

def open_file():
    browse_text.set("loading...")
    file = askopenfile(root, mode='r', title="Choose a file", filetype=[("pdf file", "*.pdf")])
    if file:
        read_file = PyPDF2.PdfFileReader(file)
        page = read_file.getPage(0)
        page_content = page.extractText()

        text_box = tk.Tex(root, height=10, width=50, padx=15, pady=15)
        text_box.insert(1.0, page_content)
        text_box.grid(column=1, row=3)

browse_text = tk.StringVar();
browse_btn = tk.Button(root, textvariable=browse_text, command=lambda: open_file(), bg="blue", fg="white", font="arial", height=3, width=15)
browse_text.set("Open file")

Answer 1

askopenfile 不接受 根参数。

>>> from tkinter.filedialog import askopenfile
>>> help(askopenfile)
Help on function askopenfile in module tkinter.filedialog:

askopenfile(mode='r', **options)
    Ask for a filename to open, and returned the opened file

所以只需更改

file = askopenfile(root, mode='r', title="Choose a file", filetype=[("pdf file", "*.pdf")])

为

file = askopenfile(mode='r', title="Choose a file", filetype=[("pdf file", "*.pdf")])