使用 swift 执行 MacOS 中应用程序包中的 shell 脚本

发布于 2025-01-09 22:50:22 字数 1098 浏览 0 评论 0原文

我试图找出是否可以在 swift 中执行位于我的应用程序包中的 shell 脚本。它是一个禁用沙盒的 Mac 应用程序。

这就是我获取 url 并且它正在工作的方式：

guard let saveScriptURL = Bundle.main.url(forResource: "scripts/save", withExtension: "sh") else {
            VsLogger.logDebug("***", "Unable to get save.sh file")
            return false
        }

返回 this

/Users/me/Library/Developer/Xcode/DerivedData/appName-fcowyecjzsqnhrchpnwrtthxzpye/Build/Products/Debug/appName.app/Contents/Resources/scripts/save.sh

然后这是我运行它的代码。

  func shell(_ scriptURL: URL) throws {
        let task = Process()
        let pipe = Pipe()
        task.standardOutput = pipe
        task.standardError = pipe
        task.executableURL =  scriptURL
        try task.run()
    }

但我收到错误：

Error Domain=NSCocoaErrorDomain Code=4 "The file “save.sh” doesn’t exist." UserInfo={NSFilePath=/Users/me/Library/Developer/Xcode/DerivedData/appName-fcowyecjzsqnhrchpnwrtthxzpye/Build/Products/Debug/appName.app/Contents/Resources/scripts/save.sh}

任何指针都值得赞赏。

原文

I'm trying to find out if is it possible to execute a shell script located in my app bundle in swift. It is a Mac application with Sandbox disabled.

This is how I get the url and it is working:

guard let saveScriptURL = Bundle.main.url(forResource: "scripts/save", withExtension: "sh") else {
            VsLogger.logDebug("***", "Unable to get save.sh file")
            return false
        }

which returns this

/Users/me/Library/Developer/Xcode/DerivedData/appName-fcowyecjzsqnhrchpnwrtthxzpye/Build/Products/Debug/appName.app/Contents/Resources/scripts/save.sh

then this is my code to run it.

  func shell(_ scriptURL: URL) throws {
        let task = Process()
        let pipe = Pipe()
        task.standardOutput = pipe
        task.standardError = pipe
        task.executableURL =  scriptURL
        try task.run()
    }

but I get the error:

Error Domain=NSCocoaErrorDomain Code=4 "The file “save.sh” doesn’t exist." UserInfo={NSFilePath=/Users/me/Library/Developer/Xcode/DerivedData/appName-fcowyecjzsqnhrchpnwrtthxzpye/Build/Products/Debug/appName.app/Contents/Resources/scripts/save.sh}

Any pointers are appreciated.

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哭泣的笑容 2025-01-16 22:50:22

您的代码存在一些问题需要修复。

首先，您错误地使用了 Process，属性 executableURL 用于可执行文件，即本例中的 shell，您想用于运行脚本，因此对于 zsh 来说，它应该设置为

task.executableURL = URL(fileURLWithPath: "/bin/zsh")

其次，似乎经过一番尝试和错误后，我们无法直接执行脚本，我认为这是因为即使我们使用 chmod 将脚本设置为可执行文件，当脚本复制到捆绑包时，它也会丢失。因此，脚本需要作为“source save.sh”运行

要设置要运行的脚本，我们使用 arguments 属性

task.arguments = ["-c", "source \(scriptURL.path"]

因此，您的 shell 函数就变成了

func shell(_ scriptURL: URL) throws {
    let task = Process()
    let pipe = Pipe()
    task.standardOutput = pipe
    task.standardError = pipe

    task.executableURL = URL(fileURLWithPath: "/bin/zsh")
    task.arguments = ["-c", "source \(scriptURL.path)"]
    try task.run()
}

There are some issues with your code that needs to be fixed.

Firstly you are using Process incorrectly, the property executableURL is meant for the executable, that is the shell in this case, you want to use for running your script so for zsh it should be set to

task.executableURL = URL(fileURLWithPath: "/bin/zsh")

Secondly it seems after some trial and error that we can not execute the script directly, I assume this is because even if we set the script as executable using chmod this is lost when the script is copied to the bundle. So the script needs to be run as "source save.sh"

To set the script to be run we use the arguments property

task.arguments = ["-c", "source \(scriptURL.path"]

So together your shell function becomes

func shell(_ scriptURL: URL) throws {
    let task = Process()
    let pipe = Pipe()
    task.standardOutput = pipe
    task.standardError = pipe

    task.executableURL = URL(fileURLWithPath: "/bin/zsh")
    task.arguments = ["-c", "source \(scriptURL.path)"]
    try task.run()
}

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