jq 无法使用 join 迭代数字
我想从 json 文件中添加一些由管道分隔的值。到目前为止，它运行良好，直到值是数字而不是字符串为止。
这是我到目前为止所做的：jq -r '.content[] | {季节标题、编号、名称} | join("|")' file.json
我尝试将数字转换为字符串，但没有成功jq -r '.content[] | {seasonTitle, "episodeNumber|tostring", name} | join("|")' file.json
实际结果：
Top Master||Last Chance / Season 12
Top Master||Épisode 8 / Season 12
Top Master||Épisode 7 / Season 12
预期结果：
Top Master|236|Last Chance / Season 12
Top Master|235|Épisode 8 / Season 12
Top Master|234|Épisode 7 / Season 12
这里是 file.json
{
"page": 0,
"size": 3,
"count": 3,
"content": [
{
"name": "Last Chance / Season 12",
"releaseDate": "2008",
"duration": 2100,
"episodeNumber": 236,
"title": "Last Chance / Season 12",
"seasonTitle": "Top Master"
},
{
"name": "Épisode 8 / Season 12",
"releaseDate": "2008",
"duration": 7320,
"episodeNumber": 235,
"title": "Épisode 8 / Season 12",
"seasonTitle": "Top Master"
},
{
"name": "Épisode 7 / Season 12",
"releaseDate": "2008",
"duration": 7200,
"episodeNumber": 234,
"title": "Épisode 7 / Season 12",
"seasonTitle": "Top Master"
}
]
}
I would like to add some values from json file separated by pipe. It's working well so far until a value is a number and not a string.
Here what I've done so far: jq -r '.content[] | {seasonTitle, number, name} | join("|")' file.json
I've tried to convert number to string without any success jq -r '.content[] | {seasonTitle, "episodeNumber|tostring", name} | join("|")' file.json
Actual Result:
Top Master||Last Chance / Season 12
Top Master||Épisode 8 / Season 12
Top Master||Épisode 7 / Season 12
Expected Result:
Top Master|236|Last Chance / Season 12
Top Master|235|Épisode 8 / Season 12
Top Master|234|Épisode 7 / Season 12
Here the file.json
{
"page": 0,
"size": 3,
"count": 3,
"content": [
{
"name": "Last Chance / Season 12",
"releaseDate": "2008",
"duration": 2100,
"episodeNumber": 236,
"title": "Last Chance / Season 12",
"seasonTitle": "Top Master"
},
{
"name": "Épisode 8 / Season 12",
"releaseDate": "2008",
"duration": 7320,
"episodeNumber": 235,
"title": "Épisode 8 / Season 12",
"seasonTitle": "Top Master"
},
{
"name": "Épisode 7 / Season 12",
"releaseDate": "2008",
"duration": 7200,
"episodeNumber": 234,
"title": "Épisode 7 / Season 12",
"seasonTitle": "Top Master"
}
]
}
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您正在使用
join来连接不同类型的值，这在 jq v1.6 下工作正常：演示
但是，对于 jq v1.5 则不然，您需要使用
tostring将非字符串转换为字符串。当您使用快捷方式为join创建对象时，引入此转换会牺牲解决方案的简洁性。因此，要么坚持使用它：要么使用数组，因为无论如何您都只需要值：
You are using
jointo concatenate values of different types, which works fine under jq v1.6:Demo
However, with jq v1.5 it doesn't, and you need to convert non-strings to strings using
tostring. As you are using a shortcut to create an object forjoin, introducing this conversion sacrifices the conciseness of your solution. So either stick with it:Or use an array instead, as you are going for the values only anyway: