如何在C中将2个字符串提取到单独的数组中

Question

该程序的目标是将编辑字符串中的给定单词替换为完整句子中的星号。

例如给出一个完整的句子：“敏捷的棕色狐狸跳过了懒狗” 并编辑字符串：“the，jumps，lazy”，输出为“***quickbrownfox*****over*******dog”，需要保存在result.txt中。

我的主要想法是在搜索单词之前首先将编辑字符串和完整句子提取到数组中。如果匹配，则完整句子的数组将替换为星号。最后，数组被转换回字符串。

我的代码的问题是，我想将 fullSentence[] 和 redactString[] 中的字符串提取到单独的数组中，但是当我运行此代码时，它输出

... 跳跃， 懒惰的 这 Y├╠╠╠╠╠╠j

这是代码：

int main(void) {

    char fullSentence[] = "The quick brown fox jumps over the lazy dog";
    int t = 0;
    int i = 0;
    char **redactArray = NULL;
    char *token = strtok(fullSentence, " ");


    char redactString[] = "the, jumps, lazy";
    int j = 0;
    char *p = strtok (redactString, ", ");
    char *extractString[3];


    for (t = 1; token; ++t) { // Extract fullSentence[]
        redactArray = realloc(redactArray, t *sizeof(*redactArray));       
        redactArray[t - 1] = malloc(strlen(token) + 1);
        strncpy(redactArray[t - 1], token, strlen(token) + 1);
        token = strtok(NULL, " ");
    }

    for (i = 0; i < t-1; ++i){
        printf("%s\n", redactArray[i]);
    }


    while (p != NULL) { // Extract redactString[]
        extractString[j++] = p;
        p = strtok(NULL, ", ");
    }

    for (j = 0; j < sizeof(extractString); ++j) {
        printf("%s\n", extractString[j]);
    }

    return extractString;
}

提前致谢:)

Answer 1

请您尝试以下操作：

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

int main(void) {
    char fullSentence[] = "The quick brown fox jumps over the lazy dog";
    char **fullArray = NULL;    // tokenized array for fullSentence
    int m = 0;                  // array length of fullArray

    char redactString[] = "the, jumps, lazy";
    char **redactArray = NULL;  // tokenized array for redactString
    int n = 0;                  // array length of redactArray

    char *token;
    int i, j, k;

    for (token = strtok(fullSentence, " "); token != NULL; token = strtok(NULL, " ")) {
        fullArray = realloc(fullArray, (m + 1) * sizeof(*fullArray));
        fullArray[m] = malloc(strlen(token) + 1);
        strncpy(fullArray[m], token, strlen(token) + 1);
        m++;
    }

    for (token = strtok(redactString, ", "); token != NULL; token = strtok(NULL, ", ")) {
        redactArray = realloc(redactArray, (n + 1) * sizeof(*redactArray));
        redactArray[n] = malloc(strlen(token) + 1);
        strncpy(redactArray[n], token, strlen(token) + 1);
        n++;
    }

    // compare the words one by one ignoring case
    for (i = 0; i < m; i++) {
        for (j = 0; j < n; j++) {
            if (strcasecmp(fullArray[i], redactArray[j]) == 0) {
                // the words match. redact the word in fullArray[i]
                for (k = 0; k < strlen(fullArray[i]); k++) {
                    fullArray[i][k] = '*';
                }
            }
        }
    }

    // print the redacted string
    for (i = 0; i < m; i++) {
        printf("%s%s", fullArray[i], i == m - 1 ? "\n" : " ");
    }

    return 0;
}

输出：

*** quick brown fox ***** over *** **** dog