python 中的文件夹操作

发布于 2025-01-09 20:03:04 字数 412 浏览 0 评论 0原文

我的 xpto 文件夹中有许多名为 0、0.05、0.1、0.2、folder1、folder2 的文件夹。我只想获取以数字命名的文件夹（它们始终在 0 和 2 之间）并移动到另一个文件夹。所以，我想知道我需要移动哪些文件夹并且我正在尝试打印它们。该代码没有回答任何问题！

import os
import shutil
import numpy as np

pasta="xpto"

lista=[]
lst=np.arange(0.05,1,0.05).round(2)
for i in lst:
    lista.append(i)

for foldername in os.listdir(os.path.join(xpto)):
    if foldername in lista:
        print(foldername)

原文

I have many folders named as 0, 0.05, 0.1, 0.2, folder1, folder2 inside my xpto folder.
I want to get only the folders named with numbers (they are always between 0 and 2) and move to another folder.
So, I want to know what folders I need to move and I'm trying to print them. The code doesn't answer anything!

import os
import shutil
import numpy as np

pasta="xpto"

lista=[]
lst=np.arange(0.05,1,0.05).round(2)
for i in lst:
    lista.append(i)

for foldername in os.listdir(os.path.join(xpto)):
    if foldername in lista:
        print(foldername)

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不弃不离 2025-01-16 20:03:04

我不知道为什么你使用 numpy 来进行基本数学和目录代码，但基本上你只想迭代你的 listdir 并检查你想要的名称：

for folder in os.listdir(...):
   if folder[0] in ('0', '.', '1', '2'):
       # something
   # or use other logic like parse the foldername:
   try:
       number = float(folder)
   except ValueError:
       # not a number
   else:
       # it is a number

I don't know why you're using numpy for basic math and directory code, but basically you just want to iterate over your listdir and check the name anyway you want:

for folder in os.listdir(...):
   if folder[0] in ('0', '.', '1', '2'):
       # something
   # or use other logic like parse the foldername:
   try:
       number = float(folder)
   except ValueError:
       # not a number
   else:
       # it is a number

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