螺旋矩阵出现动画

Question

我正在尝试制作一个螺旋矩阵，但是当我尝试让数字一一出现时，它只一一显示线条。

请帮忙！

import numpy as np
from time import sleep

n = int(input("Width : "))
k = int(input("Space : "))

a = np.zeros((n,n))
print(a/n)

i = 0 #i line
j = 0 #j column
it = -1 #it upper line
id = n #id downer line
jt = -1 #jt left column
jp = n #jp right column
x = k #x starter number

while j < jp:

    while j < jp:
        a[i][j] = x
        x += k
        j +=1
    it +=1
    i=it+1
    j=jp-1

    while i< id:
        a[i][j] = x
        x += k
        i +=1
    jp -=1
    j=jp-1
    i=id-1

    while j > jt:
        a[i][j] = x
        x += k
        j -=1
    id -=1
    i=id-1
    j=jt+1

    while i>it:
        a[i][j] = x
        x += k    
        i -=1
    jt +=1
    i=it+1
    j=jt+1

for x in a:
    print(x)
    sleep(0.1)

下面是一个示例：

每个数字都应该一一出现。

（我只是将其放在这里，以便我可以发布此内容，因为我需要添加更多详细信息）

Answer 1

不是很微不足道。

我找到了一个使用空字符数组和光标操作的解决方案。
这应该会产生所需的输出：

# replace your last "for x in a" loop by the following

def print_array(arr, block_size=4):
    """
    prints a 2-D numpy array in a nicer format
    """
    for a in arr:
        for elem in a:
            print(elem.rjust(block_size), end="")
        print(end="\n")

# empty matrix which gets filled with rising numbers
matrix_to_be_filled = np.chararray(a.shape, itemsize=3, unicode=True)

for _ in range(a.size):
    # find position of minimum
    row, col = np.unravel_index(a.argmin(), a.shape)
    # add minimum at correct position
    matrix_to_be_filled[row, col] = f'{a.min():.0f}'
    # write partially filled matrix
    print_array(matrix_to_be_filled)
    # delete old minimum in a-matrix
    a[row, col] = a.max()+1
    sleep(0.1)
    # bring cursor back up except for last element
    if _ < a.size-1:
        print('\033[F'*(matrix_to_be_filled.shape[0]+1))

如果您使用的是 pycharm，则需要编辑 运行/调试配置并激活“在输出控制台中模拟终端”以使特殊的“向上移动”字符起作用