(Python) 如何反转列表项的字符
我想反转列表中每个项目的字符顺序
myList = ['78', '79', '7a'] 并且我希望它获得输出 87 97 a7到目前为止
我已经尝试过：
newList = [x[::-1] for x in myList][::-1]
这
def reverseWord(word):
return word[::-1]
myList = ['78', '79', '7a']
newList = [reverseWord(word) for word in myList]
将返回原始列表或反转整个列表而不仅仅是项目
I want to reverse character order of every item in a list
I have myList = ['78', '79', '7a'] and I want it to get the output 87 97 a7
so far I've tried:
newList = [x[::-1] for x in myList][::-1]
and
def reverseWord(word):
return word[::-1]
myList = ['78', '79', '7a']
newList = [reverseWord(word) for word in myList]
this would either return the original list or reverse the entire list and not just the items
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评论（3）
在您的行
[x[::-1] for x in myList][::-1]中，最后的[::-1]确实反转了列表，你不需要它你缺少的只是格式：使用空格连接元素
In your line
[x[::-1] for x in myList][::-1], the final[::-1]does reverse the list, you don't need itWhat you missing is only formatting : join the element using a space
由于您尝试仅反转列表中的项目而不是列表本身，因此您只需要删除额外的
[::-1]，因此您的代码应如下所示：使用
reverseWord方法的第二个代码是正确的，并且可以准确地为您提供所需的输出。Since your trying to reverse only the items inside the list and not the list it-self you only need to remove the extra
[::-1],so your code should look like this:In addition your second code using the
reverseWordmethod is correct and gives you exactly the output you wanted.好吧，一句话就能完成这项工作：
Well, a one-liner to do the job :