Mysql:如何用2个不同的条件查询1个表并在单独的列中显示结果
我有 1 个名为 ItemDelivery 的表。我想获取每月具有 DeliveryDate 的商品数量和已收到日期的商品数量。某些商品的“deliveryDate”月份具有不同的“receiveDate”月份,例如计划在该月下旬配送的商品将在下个月的月初收到。有些可能需要几个月的时间才能运送到海外。
这是数据:
id iditem deliveryDate receiveDate
1 2 2021-01-03 2021-01-05
2 2 2021-01-03
3 3 2021-02-05 2021-02-06
4 5 2021-02-05
5 4 2021-02-20 2021-03-01
6 3 2021-03-15 2021-04-08
我想要
Mo Delivery Recieve
Jan 2 1
Feb 3 1
Mar 1 1
Apr 0 1
这个查询仅给出 1 列
select date_format(deliveryDate,'%b') as mo ,
count(id) as delivery
from ItemDelivery
where year(deliveryDate)=2021
group by month(deliveryDate)
union all
select date_format(receiveDate,'%b') as mo ,
count(id) as received
from ItemDelivery
where year(receiveDate)=2021
group by month(receiveDate)
输出:
Mo Delivery
Jan 2
Feb 3
Mar 1
Jan 1
Feb 1
Mar 1
Apr 1
这个查询也有不同的输出
SELECT d1.mo, d1.delivery, d2.received
FROM
(SELECT month(deliveryDate) as mo, count(id) AS delivery
FROM ItemDelivery
WHERE year(deliveryDate)=2021 group by month(deliveryDate)) as d1,
(SELECT month(receiveDate) as mo, count(id) AS received
FROM ItemDelivery
WHERE year(receiveDate)=2021 group by month(receiveDate)) as d2
输出:
mo delivery received
1 2 1
2 3 1
3 1 1
1 2 1
2 3 1
3 1 1
1 2 1
2 3 1
3 1 1
1 2 1
2 3 1
3 1 1
这也有相同的输出,除非我使用条件 d1.mo=d2.mo:
select d1.mo, d1.delivery, d2.received
from
(SELECT month(deliveryDate) as mo, count(id) as delivery
FROM ItemDelivery
WHERE year(deliveryDate)=2021 group by month(deliveryDate)) d1
inner join
(SELECT month(receiveDate) as mo, count(id) as received
FROM ItemDelivery
WHERE year(receiveDate)=2021 group by month(receiveDate)) d2
有什么建议吗?
I have 1 table named ItemDelivery. I wanted to get the count of items that has DeliveryDate and the items that has been receivedDate per month. Some items deliveryDate month have different receiveDate month such as items scheduled for delivery on the later part of the month would be received on early days of succeeding month. Some may take months to be delivered for overseas.
This is the data:
id iditem deliveryDate receiveDate
1 2 2021-01-03 2021-01-05
2 2 2021-01-03
3 3 2021-02-05 2021-02-06
4 5 2021-02-05
5 4 2021-02-20 2021-03-01
6 3 2021-03-15 2021-04-08
I would like to have
Mo Delivery Recieve
Jan 2 1
Feb 3 1
Mar 1 1
Apr 0 1
This query gives 1 columns only
select date_format(deliveryDate,'%b') as mo ,
count(id) as delivery
from ItemDelivery
where year(deliveryDate)=2021
group by month(deliveryDate)
union all
select date_format(receiveDate,'%b') as mo ,
count(id) as received
from ItemDelivery
where year(receiveDate)=2021
group by month(receiveDate)
Output:
Mo Delivery
Jan 2
Feb 3
Mar 1
Jan 1
Feb 1
Mar 1
Apr 1
This query also have different output
SELECT d1.mo, d1.delivery, d2.received
FROM
(SELECT month(deliveryDate) as mo, count(id) AS delivery
FROM ItemDelivery
WHERE year(deliveryDate)=2021 group by month(deliveryDate)) as d1,
(SELECT month(receiveDate) as mo, count(id) AS received
FROM ItemDelivery
WHERE year(receiveDate)=2021 group by month(receiveDate)) as d2
Output:
mo delivery received
1 2 1
2 3 1
3 1 1
1 2 1
2 3 1
3 1 1
1 2 1
2 3 1
3 1 1
1 2 1
2 3 1
3 1 1
This has also the same output except if I use condition d1.mo=d2.mo:
select d1.mo, d1.delivery, d2.received
from
(SELECT month(deliveryDate) as mo, count(id) as delivery
FROM ItemDelivery
WHERE year(deliveryDate)=2021 group by month(deliveryDate)) d1
inner join
(SELECT month(receiveDate) as mo, count(id) as received
FROM ItemDelivery
WHERE year(receiveDate)=2021 group by month(receiveDate)) d2
Any suggestions ?
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