在我的 HTML 中使用下拉选项的 PHP 代码无法正常工作。我使用 POST 作为检索方法，它导致 404 消息

Question

我是否不应该使用 POST 方法来获取员工的信息？我以前用过这个表格，当时它只有姓名、电子邮件和电话，效果很好。我是 PHP 新手，有点迷失。

我编辑了一些表单，这样它就不会永远持续下去，所以我对冗长的代码表示歉意（这是我的第一篇文章）我真的只是专注于将表单的下拉菜单转换为 PHP 因为我相信这是我真正的问题。

这是我的下拉 HTML（已编辑）

<form action="solutions_form.php" method="post" >
<div class="ai-s7-row2">
                        <label for="">phone</label>
                        <input type="text" name="phone" required="required" placeholder="Enter your phone">
                    </div>
                    
                    <div class="ai-s7-row2">
                    <label for="">website</label>
                        <input type="text" name="website" required="required" placeholder="Enter your website">
                    </div>
                    
                    <div class="ai-s7-row3 form-message-area">
                        <label for="">tell us a little about your business's compliance and/or regulartory needs</label>
                        <textarea name="message" required="required" placeholder="Enter your message"></textarea>
                    </div>
                    
                    <div class="ai-s7-row2">
                        <label for="employees">number of employees</label>
                    <div class="ai-s7-row3">
                     <select id="employees" name="employees">
        <option value=""> Pick an option</option>
        <option value="< 10"> &#60; 10</option>
        <option value="< 100">&#60; 100</option>
        <option value="< 1000">&#60; 1000</option><option value="> 1000">more than 1000</option>
      </select>
</div>
                        </div>
                    <div class="form-btn-bx">
                        <input type="submit" class="form-submit-btn" value="Submit">
                    </div>
                </form>
     

This what I have in my PHP

    /* Data Variables */

    $name = $_POST['name'];
    $email = $_POST['email'];
    $organization = $_POST['organizatioon'];
    $industry = $_POST['$industry'] ;
    $phone = $_POST['phone'];
    $website = $_POST['website'];
    $message = $_POST['message'];
    $employees = $_POST['employees'];
    $honeypot = $_POST['_honey'];
    
    
    
    $body = <<<EOD
    <br><hr><br>
    Name: $name <br>
    Email: $email <br>
    Organization: $organization <br>
    Industry: $industry <br>
    Phone: $phone <br>
    Website: $website <br>
    Message: $message <br>
    Employees: $employees <br>
    
    EOD;
    $headers = "From: $email\r\n";
    $headers .= "Content-type: text/html\r\n";
    $success = mail($webMaster, $emailSubject, $body,
    $headers);

Answer 1

需要添加form,method = "post" action = 'PHP文件地址'