在python中提取四分之一圆内的像素
我有一张图像，我想提取其中特定部分的像素。这部分是四分之一圆，我的愿望是获得它的像素。
我有中心的坐标以及线连接到圆的点。怎么可能只提取四分之一而忽略其他部分呢？
I have an image which I want to extract the pixels of the specific part of that. This part is a quarter circle, and my desire is to obtain the pixels of that.
I have the coordinates of the center and points which the lines connected to the circle. How is it possible to extract one quarter and ignore other parts?
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圆盘具有方程
(X-Xc)²+(Y-Yc)²≤R²。在中心相交的半平面有方程
c(X-Xc) + s(Y-Yc)≥0，其中c和s为角度的余弦和正弦。因此，扫描图像（或仅扫描圆的边界框）并考虑像素
(X, Y)，以满足三个约束。The disk has the equation
(X-Xc)²+(Y-Yc)²≤R².The half planes meeting at the center have equations
c(X-Xc) + s(Y-Yc)≥0wherecandsare the cosine and sine of the angle.Hence, scan the image (or just the bounding box of the circle) and consider the pixels
(X, Y)such that the three constraints are satisfied.