如何正确处理从渲染到纹理获得的深度数据范围？

发布于 2025-01-09 00:08:16 字数 464 浏览 5 评论 0原文

我正在对连接到内部格式 GL_DEPTH_STENCIL 的纹理的深度缓冲区进行一些自定义的 2D 渲染。在片段着色器中，归一化的 Z 值（仅使用 0.0 到 1.0，我很懒）是从某个进程显式写入的：

in float some_value;
uniform float max_dist;
void main()
{
    float dist = some_process( some_value );
    gl_FragDepth = clamp( dist / max_dist, 0.0, 1.0 );
}

现在我需要在 CPU 端对生成的位图执行进一步的处理。但是，glGetTexImage 将为您提供深度模板数据的 GL_UNSIGNED_INT_24_8 二进制格式。我应该如何处理 24 位深度组件？ [-1.0, 1.0] 的标准化浮点 Z 值如何映射到 24 位整数？

原文

I'm doing some customized 2D rendering to depth buffer that connects to a texture of internal format GL_DEPTH_STENCIL. In fragment shader, the normalized Z value (only 0.0 to 1.0 is used, I'm lazy) is explicitly written from some process:

in float some_value;
uniform float max_dist;
void main()
{
    float dist = some_process( some_value );
    gl_FragDepth = clamp( dist / max_dist, 0.0, 1.0 );
}

Now I need to perform further process on the resultant bitmap on CPU side. However, glGetTexImage would give you GL_UNSIGNED_INT_24_8 binary format for a depth-stencil data. What should I do with the 24-bit depth component? How does the normalized floating-point Z value of [-1.0, 1.0] map to the 24-bit integer?

分享到QQ

分享到微博