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如何将贝塞尔曲线转换为box2d对象？

发布于 2025-01-08 19:08:34 字数 71 浏览 0 评论 0原文

我正在使用贝塞尔曲线绘制线条，我需要将该贝塞尔曲线转换为 box2d 对象。我可以在 box2d 中使用哪个对象？有什么建议吗？

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生生漫 2025-01-15 19:08:34

尝试理解它......

+(b2ChainShape)curveWithPoints:(CGPoint*)points Times:(int)times
{
    //points.count must be 3
    b2ChainShape shape;
    float step = 1/(float)times;
    float t = 0;
    b2Vec2 *p = new b2Vec2[times];
    b2Vec2 v1 = [CCMethod toMeter:points[0]];
    b2Vec2 v2 = [CCMethod toMeter:points[1]];
    b2Vec2 v3 = [CCMethod toMeter:points[2]];
    for(int i = 0;i < times;i++){
        b2Vec2 pa = v1;
        pa *= ( (t-1)*(t-1)*0.5 );
        b2Vec2 pb = v2;
        pb *= ( (-t)*t+t+0.5 );
        b2Vec2 pc = v3;
        pc *= ( t*t*0.5 );
        p[i] = pa+pb+pc;
        t+=step;
    }
    shape.CreateChain(p, times);
    return shape;
}

接下来您唯一需要做的就是用这个形状创建主体和夹具。
我希望它对你充满希望......

Try to understand it...

+(b2ChainShape)curveWithPoints:(CGPoint*)points Times:(int)times
{
    //points.count must be 3
    b2ChainShape shape;
    float step = 1/(float)times;
    float t = 0;
    b2Vec2 *p = new b2Vec2[times];
    b2Vec2 v1 = [CCMethod toMeter:points[0]];
    b2Vec2 v2 = [CCMethod toMeter:points[1]];
    b2Vec2 v3 = [CCMethod toMeter:points[2]];
    for(int i = 0;i < times;i++){
        b2Vec2 pa = v1;
        pa *= ( (t-1)*(t-1)*0.5 );
        b2Vec2 pb = v2;
        pb *= ( (-t)*t+t+0.5 );
        b2Vec2 pc = v3;
        pc *= ( t*t*0.5 );
        p[i] = pa+pb+pc;
        t+=step;
    }
    shape.CreateChain(p, times);
    return shape;
}

The only thing you need to do next is to create body and fixture with this shape.
I hope it is hopeful to you ...

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