将结构传递给函数会产生嵌套结构
当我将结构传递给需要结构的函数时，该函数会嵌套在另一个结构中。
例如：
function getAnswerFromSO(struct question=StructNew()) {
writeDump(arguments.question);
}
调用getAnswerFromSO(question=myStruct); 会导致
question {
myStruct = {
text = 'foo',
subj = 'bar',
user = 1 }
};
** 显然，这不是cfdump 输出的样子，但它同样说明了问题。
有没有办法防止这种嵌套？
When I pass a struct to a function that is expecting a struct, the function is nested inside another struct.
For example:
function getAnswerFromSO(struct question=StructNew()) {
writeDump(arguments.question);
}
CallinggetAnswerFromSO(question=myStruct); results in
question {
myStruct = {
text = 'foo',
subj = 'bar',
user = 1 }
};
** Obviously, this is not what a cfdump output looks like, but it illustrates the issue just the same.
Is there a way to prevent this nesting?
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我可以确认 Ray 的示例也适用于 CF9。
I can confirm that Ray's example works on CF9 as well.