无法使 php 条件化“if”在 HTML 中工作
我的代码如下；
<select class="reg_field_field" id="user_address_state" name="user_address_state" tabindex="7">
<option value="AL" <?php if($state=='AL') echo 'selected';?>/>Alabama</option>
<option value="AK" <?php if($state=='AK') echo 'selected';?>/>Alaska</option>
<option value="AZ" <?php if($state=='AZ') echo 'selected';?>/>Arizona</option>
....
</select>
结果显示的是状态名称，它显示“注意：未定义的变量...”。
我在其他服务器上尝试过并工作，可能是 php.ini 配置？？？ php.ini 上可以有什么？
的帮助
谢谢你
my code is the following;
<select class="reg_field_field" id="user_address_state" name="user_address_state" tabindex="7">
<option value="AL" <?php if($state=='AL') echo 'selected';?>/>Alabama</option>
<option value="AK" <?php if($state=='AK') echo 'selected';?>/>Alaska</option>
<option value="AZ" <?php if($state=='AZ') echo 'selected';?>/>Arizona</option>
....
</select>
And the result is showing me instead the state name, it show "Notice: Undefined variable...".
I tried this in other server and worked, could be the php.ini configuration???
What can be on php.ini?
Thank you for any help
Ale
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该错误告诉您问题：
$state未定义。您需要检查代码以确定应在何处定义$state并确保其设置正确。如果您尝试将用户输入保存到
$state变量，请查找如下行：如果不存在，请在帖子中包含的行之前创建它。
The error tells you the problem:
$stateis undefined. You need to examine your code to determine where$stateshould be defined and ensure that it is being set properly.If you are attempting to save user input to the
$statevariable, look for a line like:If it does not exist, create it prior to the lines you included in your post.
$state 有默认值吗？在检查它是否与另一个匹配之前，它必须具有一个值。
does $state have a default value? It has to have a value prior to checking to see if it matches against another.