Android - 使用 Httppost 将一些数据从 android 应用程序传递到 servlet，但在 servlet 中变为 null

Question

//Here is my Eclipse, suppose i already get the heartvalue and oxygenvalue in other method call
private OnClickListener upload = new OnClickListener()
{
    public void onClick(View v)
    {
        ArrayList<NameValuePair> namevaluepairs = new ArrayList<NameValuePair>(2);
        namevaluepairs.add(new BasicNameValuePair("o2",oxygenvalue));
        namevaluepairs.add(new BasicNameValuePair("heart",heartvalue));
        try {
            HttpClient httpclient = new DefaultHttpClient();
            HttpPost httppost = new HttpPost("http://www2.comp.polyu.edu.hk:8080/08065312D/servlet/ServletTest"); 
            httppost.setEntity(new UrlEncodedFormEntity(namevaluepairs));
            HttpResponse response = httpclient.execute(httppost);
            HttpEntity entity = response.getEntity();
            Log.d("d", response.toString());
            InputStream is = entity.getContent();
            BufferedReader reader = new BufferedReader(new InputStreamReader(is, "iso-8859-1"), 8);
            StringBuilder sb = new StringBuilder();
            String line = null;
            while ((line = reader.readLine()) != null) {
                sb.append(line + "\n");
            }
            is.close();
            String reading = sb.toString();
            TextView lbl = (TextView) findViewById(R.id.test4);
            lbl.setText(reading);
        } catch (Exception e) {
        }

//这是我的servlet

public class FypServletTest extends HttpServlet {

public void doPost(HttpServletRequest request, HttpServletResponse response)
        throws ServletException, IOException {
        Connection con = null;
        Statement stmt = null;
        response.setContentType("text/html");
        PrintWriter out = response.getWriter();

        try {
            Class.forName("com.mysql.jdbc.Driver");
            con = DriverManager.getConnection(
                    "jdbc:mysql://mysql.comp.polyu.edu.hk:3306/", "08065312d", "xxxx");
            stmt = con.createStatement();
            stmt.execute("USE 08065312d");
            String id = "2";
            String oxygenvalue = request.getParameter("o2");
            String heartvalue = request.getParameter("heart");
            stmt = con.createStatement();
            String query="insert into Test values('"+id+"','"+oxygenvalue+"','"+heartvalue+"');";
            int rs = stmt.executeUpdate(query);
            out.flush();
            out.close();

        }
          catch(Exception ex)
            {

            }

} }

//我可以成功地将新行添加到数据库中，但参数（读数）变为空。我尝试通过在servlet中直接 println(request.getParmater("o2")) 来更改程序，但不保存到数据库，结果也是相同的（在servlet中读取变为null null）。所以我怀疑我无法获取传递给servlet的参数或者request.getParmater方法有问题，那么到底出了什么问题呢？

//我遇到的问题是发送 POST 变量，该变量似乎一直为空 //过去一周我一直在查看论坛，所有 httppost 示例几乎完全遵循这一点。如果您愿意提供任何帮助，我将不胜感激。多谢

Answer 1

首先检查这是否是 Android 问题，方法是使用 hackst.com 之类的内容发布到您的网址，然后报告后退。