python AES加密 java 解密
我有超过 1000 个图像和视频需要加密。没有什么比这更简单的了,我正在考虑使用 AES,但我不知道如何在我的计算机上加密然后解密设备上的项目。
我将使用 python 来加密我计算机上的所有项目。然后以按需方式使用java(Android应用程序)解密该项目
任何简单的解释都会做伪代码也很好。
我遇到的主要问题是如何使用相同的密钥进行加密和解密。我一直在生成密钥,但无法将其移植到其他设备进行解密。
感谢
Python 代码。工作加密和解密。
from Crypto.Cipher import AES
import os, random, struct
key = '0123456789abcdef'
mode = AES.MODE_CBC
chunksize = 64*1024
iv = ''.join(chr(random.randint(0,0xFF)) for i in range(16))
encryptor = AES.new(key,mode,iv)
filesize = os.path.getsize('sample.jpg')
with open('sample.jpg','rb') as infile:
with open('sample.enc','wb') as outfile:
outfile.write(struct.pack('<Q',filesize))
outfile.write(iv)
while True:
chunk = infile.read(chunksize)
if len(chunk) == 0:
break
elif len(chunk) % 16 != 0:
chunk += ' ' * (16 - len(chunk) % 16)
outfile.write(encryptor.encrypt(chunk))
## decrypt
with open('sample.enc', 'rb') as infile:
origsize = struct.unpack('<Q', infile.read(struct.calcsize('Q')))[0]
iv = infile.read(16)
decryptor = AES.new(key, AES.MODE_CBC, iv)
with open('sample2.jpg', 'wb') as outfile:
while True:
chunk = infile.read(chunksize)
if len(chunk) == 0:
break
outfile.write(decryptor.decrypt(chunk))
outfile.truncate(origsize)
我将如何在Java中完成解密部分?这是我的快速草率的java代码,它不起作用。我认为是填充弄乱了它。
public void decryptFile(){
String inFile = "sample.enc";
String outFile = "sample.jpg";
String dir = Environment.getExternalStorageDirectory() +"/Android/data/HOT/";
InputStream is ;
byte[] iv = new byte[16];
try {
is = new FileInputStream(dir+inFile);
is.read(iv);
} catch (FileNotFoundException e1) {
// TODO Auto-generated catch block
Log.d("D1","no file found");
} catch (IOException e) {
// TODO Auto-generated catch block
Log.d("D-2","no file found");
e.printStackTrace();
}
byte[] k = {'0','1','2','3','4','5','6','7','8','9','a','b','c','d','e','f'};
Key key = new SecretKeySpec(k,"AES");
try {
Cipher cipher = Cipher.getInstance("AES/CBC/PKCS5Padding");
cipher.init(Cipher.DECRYPT_MODE, key,new IvParameterSpec(iv));
OutputStream outs = new FileOutputStream(dir+outFile);
is = new FileInputStream(dir+inFile);
while(true){
byte[] chunk = new byte[64*1024];
is.read(chunk);
if(chunk.length == 0){
break;
}
outs.write(cipher.doFinal(chunk));
}
} catch (NoSuchAlgorithmException e) {
// TODO Auto-generated catch block
Log.d("D","1");
e.printStackTrace();
} catch (NoSuchPaddingException e) {
// TODO Auto-generated catch block
Log.d("D","2");
e.printStackTrace();
} catch (InvalidKeyException e) {
// TODO Auto-generated catch block
Log.d("D","3");
e.printStackTrace();
} catch (InvalidAlgorithmParameterException e) {
// TODO Auto-generated catch block
Log.d("D","4");
e.printStackTrace();
} catch (FileNotFoundException e) {
// TODO Auto-generated catch block
Log.d("D","5");
e.printStackTrace();
} catch (IOException e) {
// TODO Auto-generated catch block
Log.d("D","6");
e.printStackTrace();
} catch (IllegalBlockSizeException e) {
// TODO Auto-generated catch block
Log.d("D","7");
e.printStackTrace();
} catch (BadPaddingException e) {
// TODO Auto-generated catch block
Log.d("D","8");
e.printStackTrace();
}
ImageView im = (ImageView)findViewById(R.id.imageView2);
Bitmap mainBitmap = BitmapFactory.decodeFile(dir+outFile);
im.setImageBitmap(mainBitmap);
}
I have over 1000 images and videos that need to be encrypted. Nothing over the top just something simple, I was thinking of using AES but what I cannot figure out is how to encrypt on my computer then decrypt the item on the device.
I will be encrypting all the items on my computer probably using python. Then in an on demand fashion will decrypt the item with java (Android app)
Any simple explanation will do pseudo code is fine too.
The main issue im having is how to use the same key to encrypt and decrypt. I've been generating the key and can't get it to port to the other device for decryption.
Thanks
Python Code. Works encrypts and decrypts.
from Crypto.Cipher import AES
import os, random, struct
key = '0123456789abcdef'
mode = AES.MODE_CBC
chunksize = 64*1024
iv = ''.join(chr(random.randint(0,0xFF)) for i in range(16))
encryptor = AES.new(key,mode,iv)
filesize = os.path.getsize('sample.jpg')
with open('sample.jpg','rb') as infile:
with open('sample.enc','wb') as outfile:
outfile.write(struct.pack('<Q',filesize))
outfile.write(iv)
while True:
chunk = infile.read(chunksize)
if len(chunk) == 0:
break
elif len(chunk) % 16 != 0:
chunk += ' ' * (16 - len(chunk) % 16)
outfile.write(encryptor.encrypt(chunk))
## decrypt
with open('sample.enc', 'rb') as infile:
origsize = struct.unpack('<Q', infile.read(struct.calcsize('Q')))[0]
iv = infile.read(16)
decryptor = AES.new(key, AES.MODE_CBC, iv)
with open('sample2.jpg', 'wb') as outfile:
while True:
chunk = infile.read(chunksize)
if len(chunk) == 0:
break
outfile.write(decryptor.decrypt(chunk))
outfile.truncate(origsize)
How would I do the decrypt part in Java? Here is my quick sloppy java code that doesn't work. I think it is the padding that is messing it up.
public void decryptFile(){
String inFile = "sample.enc";
String outFile = "sample.jpg";
String dir = Environment.getExternalStorageDirectory() +"/Android/data/HOT/";
InputStream is ;
byte[] iv = new byte[16];
try {
is = new FileInputStream(dir+inFile);
is.read(iv);
} catch (FileNotFoundException e1) {
// TODO Auto-generated catch block
Log.d("D1","no file found");
} catch (IOException e) {
// TODO Auto-generated catch block
Log.d("D-2","no file found");
e.printStackTrace();
}
byte[] k = {'0','1','2','3','4','5','6','7','8','9','a','b','c','d','e','f'};
Key key = new SecretKeySpec(k,"AES");
try {
Cipher cipher = Cipher.getInstance("AES/CBC/PKCS5Padding");
cipher.init(Cipher.DECRYPT_MODE, key,new IvParameterSpec(iv));
OutputStream outs = new FileOutputStream(dir+outFile);
is = new FileInputStream(dir+inFile);
while(true){
byte[] chunk = new byte[64*1024];
is.read(chunk);
if(chunk.length == 0){
break;
}
outs.write(cipher.doFinal(chunk));
}
} catch (NoSuchAlgorithmException e) {
// TODO Auto-generated catch block
Log.d("D","1");
e.printStackTrace();
} catch (NoSuchPaddingException e) {
// TODO Auto-generated catch block
Log.d("D","2");
e.printStackTrace();
} catch (InvalidKeyException e) {
// TODO Auto-generated catch block
Log.d("D","3");
e.printStackTrace();
} catch (InvalidAlgorithmParameterException e) {
// TODO Auto-generated catch block
Log.d("D","4");
e.printStackTrace();
} catch (FileNotFoundException e) {
// TODO Auto-generated catch block
Log.d("D","5");
e.printStackTrace();
} catch (IOException e) {
// TODO Auto-generated catch block
Log.d("D","6");
e.printStackTrace();
} catch (IllegalBlockSizeException e) {
// TODO Auto-generated catch block
Log.d("D","7");
e.printStackTrace();
} catch (BadPaddingException e) {
// TODO Auto-generated catch block
Log.d("D","8");
e.printStackTrace();
}
ImageView im = (ImageView)findViewById(R.id.imageView2);
Bitmap mainBitmap = BitmapFactory.decodeFile(dir+outFile);
im.setImageBitmap(mainBitmap);
}
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在 Java 版本中,与 Python 版本不同,在读取 IV 之前,您似乎不会读取文件大小。
您还可以打开第二个
FileInputStream
,然后在分块读取Cipher
之前不要跳过文件大小和 IV。另一件需要检查的事情是键在 Java 和 Python 中的解释是相同的,即 Python 中的字符串与 Java 中的字节数组产生相同的字节序列。
In the Java version, you don't seem to be reading in the filesize before reading in the IV, unlike the Python version.
You also open a second
FileInputStream
and then don't skip the filesize and IV before reading in chunks for theCipher
.Another thing to check is that the keys are being interpreted the same in Java and Python, i.e. the string in Python results in the same sequence of bytes as the byte array in Java.