防止 UITextView 上的点击事件

发布于 2025-01-08 00:31:52 字数 1149 浏览 2 评论 0原文

2012-02-21 11:59:18.106 textView[20977:fe03] ;目标= <(action=延迟:, 目标=)>>

2012-02-21 11:59:18.107 textView[20977:fe03] ;目标= <(action=handlePan:, target=)>>

2012-02-21 11:59:18.108 textView[20977:fe03] ;目标= <(动作=oneFingerTripleTap:, 目标=)>; numberOfTapsRequired = 3>

2012-02-21 11:59:18.108 textView[20977:fe03] ;目标= <(动作=oneFingerDoubleTap:, 目标=)>; numberOfTapsRequired = 2>

2012-02-21 11:59:18.109 textView[20977:fe03] ;目标= <(动作=twoFingerSingleTap:, 目标=)>; numberOfTouchesRequired = 2>

2012-02-21 11:59:18.123 textView[20977:fe03] ;目标= <(action=tapAndAHalf:, target=)>>

2012-02-21 11:59:18.124 textView[20977:fe03] ;目标= <(action=twoFingerRangedSelectGesture:, target=)>>

2012-02-21 11:59:18.124 textView[20977:fe03] ;目标= <(action=oneFingerTap:, target=)>>

2012-02-21 11:59:18.129 textView[20977:fe03] ;目标= <(action=loupeGesture:, target=)>>

UITextView 上的gestureRecogniser 列表上方。我需要阻止 UITextView 上的事件:twoFingerSingleTap,但仅限此事件。有可能吗?

2012-02-21 11:59:18.106 textView[20977:fe03] ; target= <(action=delayed:, target=)>>

2012-02-21 11:59:18.107 textView[20977:fe03] ; target= <(action=handlePan:, target=)>>

2012-02-21 11:59:18.108 textView[20977:fe03] ; target= <(action=oneFingerTripleTap:, target=)>; numberOfTapsRequired = 3>

2012-02-21 11:59:18.108 textView[20977:fe03] ; target= <(action=oneFingerDoubleTap:, target=)>; numberOfTapsRequired = 2>

2012-02-21 11:59:18.109 textView[20977:fe03] ; target= <(action=twoFingerSingleTap:, target=)>; numberOfTouchesRequired = 2>

2012-02-21 11:59:18.123 textView[20977:fe03] ; target= <(action=tapAndAHalf:, target=)>>

2012-02-21 11:59:18.124 textView[20977:fe03] ; target= <(action=twoFingerRangedSelectGesture:, target=)>>

2012-02-21 11:59:18.124 textView[20977:fe03] ; target= <(action=oneFingerTap:, target=)>>

2012-02-21 11:59:18.129 textView[20977:fe03] ; target= <(action=loupeGesture:, target=)>>

Above the list of gestureRecogniser on UITextView. I need to prevent event: twoFingerSingleTap on UITextView, but only this event. there is possible?

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评论(2

梦太阳 2025-01-15 00:31:52

UITextViewUIView 的任何其他子类一样,具有 gestureRecognizers 属性,其中包含附加到视图的所有手势识别器的 NSArray。枚举该数组,找到您正在寻找的识别器并禁用它。

UITextView, as any other subclass of UIView, has gestureRecognizers property, which contains an NSArray of all gesture recognizers attached to a view. Enumerate this array, find recognizer you're looking for and disable it.

揽清风入怀 2025-01-15 00:31:52

你需要类似的东西:

for (UIGestureRecognizer *g in myTextView.gestureRecognizers)
{
    if ([g isKindOfClass:[UITapGestureRecognizer class]])
    {
        if (([(UITapGestureRecognizer *)g numberOfTouchesRequired] == 2) && ([(UITapGestureRecognizer *)g numberOfTapsRequired] == 1))
        {
            [g setEnabled: NO];
        }
    }
}

You need something like:

for (UIGestureRecognizer *g in myTextView.gestureRecognizers)
{
    if ([g isKindOfClass:[UITapGestureRecognizer class]])
    {
        if (([(UITapGestureRecognizer *)g numberOfTouchesRequired] == 2) && ([(UITapGestureRecognizer *)g numberOfTapsRequired] == 1))
        {
            [g setEnabled: NO];
        }
    }
}
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