无法从 applet 向 servlet 发送请求
我有以下代码：
URL urlServlet = new URL(WEB_SERVER_URL);
URLConnection connection = urlServlet.openConnection();
connection.setDoInput(true);
connection.setDoOutput(true);
connection.setUseCaches(false);
connection.setDefaultUseCaches(true);
connection.setRequestProperty("Content-Type", "application/octet-stream");
connection.setRequestProperty("event", "blah");
OutputStream outputStream = servletConnection.getOutputStream();
outputStream.flush();
outputStream.close();
服务器没有响应该程序。
但是，如果我从连接获取 inputStream，我会在 DoGet servlet 方法中捕获断点。
我做错了什么？
I have the following code:
URL urlServlet = new URL(WEB_SERVER_URL);
URLConnection connection = urlServlet.openConnection();
connection.setDoInput(true);
connection.setDoOutput(true);
connection.setUseCaches(false);
connection.setDefaultUseCaches(true);
connection.setRequestProperty("Content-Type", "application/octet-stream");
connection.setRequestProperty("event", "blah");
OutputStream outputStream = servletConnection.getOutputStream();
outputStream.flush();
outputStream.close();
The server is not responding to this program.
But if I get inputStream from connection, I catch breakpoint in the DoGet servlet method.
What am I doing wrong?
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评论（1）
你的错误是没有请求响应。
URLConnection是延迟执行的。仅当您请求响应时才会发送请求。调用getInputStream()实际上会触发 HTTP 请求，因为您正在请求响应。当您只是打开和关闭请求正文时，不会建立连接。另请参阅：
Your mistake was to not asking for the response. The
URLConnectionis lazily executed. The request will only be sent whenever you ask for the response. CallinggetInputStream()will actually fire the HTTP request because you're asking for the response. The connection will not be made when you just open and close the request body.See also: