The problem is with slashes: your variable contains them and the final command will be something like sed "s/string/path/to/something/g", containing way too many slashes.
Since sed can take any char as delimiter (without having to declare the new delimiter), you can try using another one that doesn't appear in your replacement string:
replacement="/my/path"
sed --expression "s@pattern@$replacement@"
Note that this is not bullet proof: if the replacement string later contains @ it will break for the same reason, and any backslash sequences like \1 will still be interpreted according to sed rules. Using | as a delimiter is also a nice option as it is similar in readability to /.
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问题出在斜杠上：你的变量包含它们，最终的命令将类似于 sed "s/string/path/to/something/g" ，包含太多斜杠。
由于 sed 可以将任何字符作为分隔符（无需声明新的分隔符），因此您可以尝试使用替换字符串中未出现的另一个字符：
请注意，这不是防弹的：如果替换字符串稍后包含
@，它会因同样的原因而中断，并且任何反斜杠序列如\1仍将根据sed规则进行解释。使用|作为分隔符也是一个不错的选择，因为它的可读性与/类似。The problem is with slashes: your variable contains them and the final command will be something like
sed "s/string/path/to/something/g", containing way too many slashes.Since
sedcan take any char as delimiter (without having to declare the new delimiter), you can try using another one that doesn't appear in your replacement string:Note that this is not bullet proof: if the replacement string later contains
@it will break for the same reason, and any backslash sequences like\1will still be interpreted according tosedrules. Using|as a delimiter is also a nice option as it is similar in readability to/.