获取上下文菜单中命令参数中的文件名
假设我的文件 Test.java 存储在： X:\S\S\nOn I\Extra but Imp\Context Menu\Ultimate Windows Context Menu Customizer\
我已经创建了一个上下文菜单，命令为 cmd /k javac -d 。 %1
输出显示长文件名，路径中包含空格。
我想要做的是从命令的上下文菜单直接编译java文件，例如：
>javac -d 。测试.java 我无法获取此信息，因为 %1 返回文件的完整路径。
我该怎么做？我的文件夹名称中有空格。
我尝试搜索很多网站...
Suppose my file Test.java is stored in : X:\S\S\nOn I\Extra but Imp\Context Menu\Ultimate Windows Context Menu Customizer\
I've created a context menu with command as cmd /k javac -d . %1
The output shows long file name with the path in which there are spaces.
What i want to do is directly compile a java file from context menu from command like :
>javac -d . Test.java
I'am not able to get this as the %1 returns the full path of file.
How can i do this ?? my folders are having spaces in there names.
I've tried to search many sites...
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您需要用双引号将您的参数括起来，并且据我所知，您不需要
cmd /k：但是，Java 编译器会出错，因为您需要匹配它所在的目录路径从 Java 源代码中定义的包调用。
您需要查看
Ant或Maven来控制您的编译。You need to surround your argument with double-quotes and you don't need the
cmd /kas far as I can tell:However the Java compiler will error as you need to match the directory path it was invoked from with the package defined in the Java source.
You need to look into
AntorMavento control your compilations.