如何测试/“驾驶” HttpRequest.java（Web 服务器）？
我正在用 java 编写简单、不复杂的 Web 服务器代码。看起来已经完成了，但我不太确定如何测试它。有人能指出我正确的方向吗？所有的编码都完成了，我只需要测试代码。我尝试从终端运行它，然后使用指定的端口连接到本地主机，但我只得到 404 NOT FOUNDs。我重申，我不认为这是代码的问题，而是我对测试驱动所述代码的方法的猜测。有想法吗？
import java.io.*;
import java.net.*;
import java.util.*;
final class HttpRequest implements Runnable {
final static String CRLF = "\r\n";
Socket socket;
// Constructor
public HttpRequest(Socket socket) throws Exception {
this.socket = socket;
}
// Implement the run() method of the Runnable interface.
public void run() {
try {
processRequest();
} catch (Exception e) {
System.out.println(e);
}
}
private static void sendBytes(FileInputStream fis, OutputStream os)
throws Exception {
// Construct a 1K buffer to hold bytes on their way to the socket.
byte[] buffer = new byte[1024];
int bytes = 0;
// Copy requested file into the socket's output stream.
while((bytes = fis.read(buffer)) != -1 ) {
os.write(buffer, 0, bytes);
}
}
private static String contentType(String fileName) {
if(fileName.endsWith(".htm") || fileName.endsWith(".html")) {
return "text/html";
}
if(fileName.endsWith(".jpeg") || fileName.endsWith(".jpg")) {
return "image/jpeg";
}
if(fileName.endsWith(".gif")) {
return "image/gif";
}
return "application/octet-stream";
}
private void processRequest() throws Exception {
// Get a reference to the socket's input and output streams.
InputStream is = socket.getInputStream();
DataOutputStream os = new DataOutputStream(socket.getOutputStream());
// Set up input stream filters.
BufferedReader br = new BufferedReader(new InputStreamReader(is));
// Get the request line of the HTTP request message.
String requestLine = new String(br.readLine());
// Display the request line.
System.out.println();
System.out.println(requestLine);
// Get and display the header lines.
String headerLine = null;
while ((headerLine = br.readLine()).length() != 0) {
System.out.println(headerLine);
}
// Extract the filename from the request line.
StringTokenizer tokens = new StringTokenizer(requestLine);
tokens.nextToken(); // skip over the method, which should be "GET"
String fileName = tokens.nextToken();
// Prepend a "." so that file request is within the current directory.
fileName = "." + fileName;
// Open the requested file.
FileInputStream fis = null;
boolean fileExists = true;
try {
fis = new FileInputStream(fileName);
} catch (FileNotFoundException e) {
fileExists = false;
}
// Construct the response message.
String statusLine = null;
String contentTypeLine = null;
String entityBody = null;
if (fileExists) {
statusLine = "200 OK" + CRLF;
contentTypeLine = "Content-type: " +
contentType( fileName ) + CRLF;
} else {
statusLine = "404 NOT FOUND" + CRLF;
contentTypeLine = "Content Not Found!" + CRLF;
entityBody = "<HTML>" +
"<HEAD><TITLE>Not Found</TITLE></HEAD>" +
"<BODY>Not Found</BODY></HTML>";
}
// Send the status line.
os.writeBytes(statusLine);
// Send the content type line.
os.writeBytes(contentTypeLine);
// Send a blank line to indicate the end of the header lines.
os.writeBytes(CRLF);
// Send the entity body.
if (fileExists) {
sendBytes(fis, os);
fis.close();
} else {
os.writeBytes("File DNE: Content Not Found!");
}
// Close streams and socket.
os.close();
br.close();
socket.close();
}
public static void main(String[] args) throws Exception {
final ServerSocket ss = new ServerSocket(8080);
while (true)
new HttpRequest(ss.accept()).run();
}
}
解决方案：
已解决。事实证明，要测试它，您需要做的就是：
1)照常从终端运行程序，
2)放置您想要尝试的文件要在单独的终端中将（假设为“example.html”）检索到与 .java 文件相同的文件夹中，
3)，请运行命令 $ wget localhost:PORT/FILE.EXTENSION
（我使用端口这里是 8080，所以 $ wget localhost:8080/example.html)
您现在应该在当前发送 wget 命令的文件夹中看到一个 html 响应文件 “200 OK”或“404 文件不是服务器”，以及文件的内容（如果前者为真）。
我把这件事过于复杂化了，评论/回复也是如此……但它已经完成了。 猜测和检查。
I am writing simple, unsophisticated web-server code in java. It seems to be finished, but I'm not quite sure how to test it. Could someone point me in the right direction? All the coding is finished, I just need to test the code. I tried running it from the terminal, and then connecting to localhost with a specified port, but I only get 404 NOT FOUNDs. I reiterate, I don't think this is a problem with the code, but with my guessing at methods by which to test drive said code. Ideas?
import java.io.*;
import java.net.*;
import java.util.*;
final class HttpRequest implements Runnable {
final static String CRLF = "\r\n";
Socket socket;
// Constructor
public HttpRequest(Socket socket) throws Exception {
this.socket = socket;
}
// Implement the run() method of the Runnable interface.
public void run() {
try {
processRequest();
} catch (Exception e) {
System.out.println(e);
}
}
private static void sendBytes(FileInputStream fis, OutputStream os)
throws Exception {
// Construct a 1K buffer to hold bytes on their way to the socket.
byte[] buffer = new byte[1024];
int bytes = 0;
// Copy requested file into the socket's output stream.
while((bytes = fis.read(buffer)) != -1 ) {
os.write(buffer, 0, bytes);
}
}
private static String contentType(String fileName) {
if(fileName.endsWith(".htm") || fileName.endsWith(".html")) {
return "text/html";
}
if(fileName.endsWith(".jpeg") || fileName.endsWith(".jpg")) {
return "image/jpeg";
}
if(fileName.endsWith(".gif")) {
return "image/gif";
}
return "application/octet-stream";
}
private void processRequest() throws Exception {
// Get a reference to the socket's input and output streams.
InputStream is = socket.getInputStream();
DataOutputStream os = new DataOutputStream(socket.getOutputStream());
// Set up input stream filters.
BufferedReader br = new BufferedReader(new InputStreamReader(is));
// Get the request line of the HTTP request message.
String requestLine = new String(br.readLine());
// Display the request line.
System.out.println();
System.out.println(requestLine);
// Get and display the header lines.
String headerLine = null;
while ((headerLine = br.readLine()).length() != 0) {
System.out.println(headerLine);
}
// Extract the filename from the request line.
StringTokenizer tokens = new StringTokenizer(requestLine);
tokens.nextToken(); // skip over the method, which should be "GET"
String fileName = tokens.nextToken();
// Prepend a "." so that file request is within the current directory.
fileName = "." + fileName;
// Open the requested file.
FileInputStream fis = null;
boolean fileExists = true;
try {
fis = new FileInputStream(fileName);
} catch (FileNotFoundException e) {
fileExists = false;
}
// Construct the response message.
String statusLine = null;
String contentTypeLine = null;
String entityBody = null;
if (fileExists) {
statusLine = "200 OK" + CRLF;
contentTypeLine = "Content-type: " +
contentType( fileName ) + CRLF;
} else {
statusLine = "404 NOT FOUND" + CRLF;
contentTypeLine = "Content Not Found!" + CRLF;
entityBody = "<HTML>" +
"<HEAD><TITLE>Not Found</TITLE></HEAD>" +
"<BODY>Not Found</BODY></HTML>";
}
// Send the status line.
os.writeBytes(statusLine);
// Send the content type line.
os.writeBytes(contentTypeLine);
// Send a blank line to indicate the end of the header lines.
os.writeBytes(CRLF);
// Send the entity body.
if (fileExists) {
sendBytes(fis, os);
fis.close();
} else {
os.writeBytes("File DNE: Content Not Found!");
}
// Close streams and socket.
os.close();
br.close();
socket.close();
}
public static void main(String[] args) throws Exception {
final ServerSocket ss = new ServerSocket(8080);
while (true)
new HttpRequest(ss.accept()).run();
}
}
Solution:
SOLVED. It turns out, to test it, all you need to do is:
1) run the program from the terminal as per usual,
2) place the file you want to try to retrieve (lets say "example.html") into the same folder as your .java file(s),
3) in a separate terminal, run the command $ wget localhost:PORT/FILE.EXTENSION
(I used port 8080 here, so $ wget localhost:8080/example.html)
You should now see, in the folder you are currently sending the wget command from, an html response file "200 OK" or "404 File Not Server", along with the contents of the file if the former is true.
I was over-complicating this, as were the comments/replies... But it's done.
Guessing and checking ftw.
如果你对这篇内容有疑问，欢迎到本站社区发帖提问 参与讨论，获取更多帮助，或者扫码二维码加入 Web 技术交流群。
绑定邮箱获取回复消息
由于您还没有绑定你的真实邮箱，如果其他用户或者作者回复了您的评论，将不能在第一时间通知您！
发布评论
评论（1）
解决了。事实证明，要测试它，您需要做的就是：
1)照常从终端运行程序，
2)放置您想要尝试的文件要在单独的终端中将（假设为“example.html”）检索到与 .java 文件相同的文件夹中，
3)，请运行命令 $ wget localhost:PORT/FILE.EXTENSION
（我使用端口8080 在这里，所以 $ wget localhost:8080/example.html)
现在，您应该在当前发送 wget 命令的文件夹中看到响应文件“200 OK”或“404 File Not Server”，以及文件的内容（如果前者为真）。
我把这件事过于复杂化了，评论/回复也是如此……但它已经完成了。
猜测和检查。
SOLVED. It turns out, to test it, all you need to do is:
1) run the program from the terminal as per usual,
2) place the file you want to try to retrieve (lets say "example.html") into the same folder as your .java file(s),
3) in a separate terminal, run the command $ wget localhost:PORT/FILE.EXTENSION
(I used port 8080 here, so $ wget localhost:8080/example.html)
You should now see, in the folder you are currently sending the wget command from, a response file "200 OK" or "404 File Not Server", along with the contents of the file if the former is true.
I was over-complicating this, as were the comments/replies... But it's done.
Guessing and checking ftw.