[mongoid][factory_girl] 如何让factory_girl在安全模式下创建？（mongoid安全模式）

发布于 2025-01-07 13:14:42 字数 479 浏览 3 评论 0原文

有没有办法让factory_girl在mongoid安全模式下创建记录？原始代码是：

@user = FactoryGirl.create( :user, email: email )

但无一例外地失败了，原因是复合索引的重复键（db被截断，但索引尚未被mongodb删除）。我必须将代码更改为：

@user = User.safely.create!({
  email: email, 
  password: Digest::MD5.hexdigest('123456')
})

这样我就可以明白为什么factory_girl 没有成功创建用户。有没有办法让factory_girl在安全模式下创建记录，例如：

@user = FactoryGirl.safely.create( :user, email: email )

谢谢

原文

Is there anyway to make factory_girl create records in mongoid safe mode??
The original code is:

@user = FactoryGirl.create( :user, email: email )

But it failed without exceptions, cause by the duplicated key of compound index (db truncated, but indexes hasn't been removed by mongodb). I have to change the code to :

@user = User.safely.create!({
  email: email, 
  password: Digest::MD5.hexdigest('123456')
})

So I can see why factory_girl didn't create the User successful.
Is there anyway to make factory_girl create record in safe mode like:

@user = FactoryGirl.safely.create( :user, email: email )

thanks

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流心雨 2025-01-14 13:14:42

这个技巧可能会有所帮助。以下测试通过：

      let(:user) { FactoryGirl.create(:user) }

      it "deletes a user" do
        user.new_record?
        expect { delete :destroy, :id => user.id }.to change(User, :count).by(-1)
      end

If - user.new_record? - 评论，测试失败。

This trick may help. The following test passes:

      let(:user) { FactoryGirl.create(:user) }

      it "deletes a user" do
        user.new_record?
        expect { delete :destroy, :id => user.id }.to change(User, :count).by(-1)
      end

If - user.new_record? - commented, test fails.

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