具有两个交叉表和多列的 Sql 数据透视表

Question

我正在尝试构建一个具有两个交叉表和多个列的表。到目前为止我已经有了这个，当我运行它时，

    create table test2(city nvarchar(10), race nvarchar(30), sex nvarchar(10), age int)
    insert into test2 values ('Austin',  'African-American', 'male', 21)
    insert into test2 values ('Austin',  'Asian', 'female', 22)
    insert into test2 values ('Austin',  'Caucasian', 'male', 23)
    insert into test2 values ('Austin',  'Hispanic', 'female', 24)
    insert into test2 values ('Austin',  'African-American', 'Unknown', 25)
    insert into test2 values ('Austin',  'Asian', 'male', 26)
    insert into test2 values ('Austin',  'Caucasian', 'female', 27)
    insert into test2 values ('Austin',  'Hispanic', 'Unknown', 28)
    insert into test2 values ('Austin',  'Asian', 'male', 29)
    insert into test2 values ('Austin',  'Caucasian', 'female', 31)
    insert into test2 values ('Dallas',  'Hispanic', 'Unknown', 32)
    insert into test2 values ('Dallas',  'African-American', 'male', 33)
    insert into test2 values ('Dallas',  'Asian', 'female', 34)
    insert into test2 values ('Dallas',  'Caucasian', 'Unknown', 35)
    insert into test2 values ('Dallas',  'Hispanic', 'male', 500)
    insert into test2 values ('Dallas',  'African-American', 'female', 36)
    insert into test2 values ('Dallas',  'Asian', 'Unknown', 37)
    insert into test2 values ('Dallas',  'Caucasian', 'male', 38)
    insert into test2 values ('Dallas',  'Hispanic', 'female', 39)
    insert into test2 values ('Dallas',  'African-American', 'Unknown', 41)
    insert into test2 values ('Houston',  'Asian', 'male', 42)
    insert into test2 values ('Houston',  'Caucasian', 'female', 43)
    insert into test2 values ('Houston',  'Hispanic', 'Unknown', 44)
    insert into test2 values ('Houston',  'African-American', 'male', 45)
    insert into test2 values ('Houston',  'Asian', 'female', 46)
    insert into test2 values ('Houston',  'Caucasian', 'Unknown', 47)
    insert into test2 values ('Houston',  'Hispanic', 'male', 48)
    insert into test2 values ('Houston',  'African-American', 'female', 49)
    insert into test2 values ('Houston',  'Asian', 'Unknown', 51)
    insert into test2 values ('Houston',  'Caucasian', 'male', 52)

    SELECT  *
    FROM
    (
    SELECT  a.city, a.sex
    FROM [AdventureWorksDW].[dbo].[test2] a

    ) p
    PIVOT
    (
    COUNT (sex)
    FOR sex
    IN ([male], [female], [Unknown])
    ) AS pvt

我得到这个

_{（来源：realestateagenthealthinsurance.com）}

但我需要的是这个，顶部有两个交叉选项卡和多列选项。

_{（来源：realestateagenthealthinsurance.com）}

这可以通过枢轴实现吗或任何其他解决方案？ 提前致谢

Answer 1

WITH T AS (
    SELECT A.city,
           A.sex, 
           CASE
                WHEN A.age BETWEEN 20 AND 30 THEN '20-30_' + race
                WHEN A.age BETWEEN 31 AND 40 THEN '31-40_' + race
                WHEN A.age BETWEEN 41 AND 50 THEN '41-50_' + race
           END AS age_range_race
    FROM @test2 AS A
)
SELECT  *
FROM T
PIVOT( COUNT(age_range_race) FOR age_range_race
       IN(
          [20-30_African-American], 
          [20-30_Asian], 
          [20-30_Caucasian], 
          [20-30_Hispanic],
          [31-40_African-American], 
          [31-40_Asian], 
          [31-40_Caucasian], 
          [31-40_Hispanic],
          [41-50_African-American], 
          [41-50_Asian], 
          [41-50_Caucasian], 
          [41-50_Hispanic]
          )
) AS P
ORDER BY city, sex

Answer 2

您可以为 3 个年龄组中的每一个运行单独的 PIVOT 查询，然后将结果外部联接到当前城市和性别的查询：

WITH DataKeys AS (
    select distinct city, sex
    from test2),
Data20to29 AS (
    SELECT *
    FROM(SELECT * FROM test2 WHERE age between 20 and 29
    ) AS Age20to29
    PIVOT (COUNT(age)
           FOR race IN ([African-American], [Asian], [Caucasian], [Hispanic])
    ) as Data20to29),
Data30to39 AS (
    SELECT *
    FROM(SELECT * FROM test2 WHERE age between 30 and 39
    ) AS Age30to39
    PIVOT (COUNT(age)
           FOR race IN ([African-American], [Asian], [Caucasian], [Hispanic])
    ) as Data30to39),
Data40to49 AS (
    SELECT *
    FROM(SELECT * FROM test2 WHERE age between 40 and 49
    ) AS Age40to49
    PIVOT (COUNT(age)
           FOR race IN ([African-American], [Asian], [Caucasian], [Hispanic])
    ) as Data40to49)
SELECT SELECT k.city, k.sex,
   d20.[African-American], d20.Asian, d20.Caucasian, d20.Hispanic,
   d30.[African-American], d30.Asian, d30.Caucasian, d30.Hispanic,
   d40.[African-American], d40.Asian, d40.Caucasian, d40.Hispanic
FROM DataKeys k LEFT JOIN Data20to29 d20 ON d20.city = k.city AND d20.sex = k.sex
LEFT JOIN Data30to39 d30 ON d30.city = k.city AND d30.sex = k.sex
LEFT JOIN Data40to49 d40 ON d40.city = k.city AND d40.sex = k.sex
ORDER BY k.city, k.sex