“无效的“..”-范围，“..”左侧没有字符”调用trim()时出错

发布于 2025-01-07 11:49:13 字数 280 浏览 0 评论 0原文

假设我有 $url="../folder/file" 并且我想查找并删除 ../ 部分。

我正在使用 trim() ……

$url = trim($url,"../");

但它给了我一个警告：

警告：trim() [function.trim]：无效的“..”范围，上一行“..”左侧没有字符

我做错了什么？

原文

Let's say I have $url="../folder/file" and I want to find and remove the ../ part.

I'm using trim() …

$url = trim($url,"../");

… but it gives me a warning:

Warning: trim() [function.trim]: Invalid '..'-range, no character to the left of '..' on line above

What I did wrong?

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§对你不离不弃 2025-01-14 11:49:13

你做错的是没有阅读手册：

使用 .. 您可以指定字符范围。

<?php
$url="../folder/file";
$url = trim($url,"\.\./");
echo $url;
?>

what you did wrong was fail to read the manual:

With .. you can specify a range of characters.

<?php
$url="../folder/file";
$url = trim($url,"\.\./");
echo $url;
?>

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烟火散人牵绊 2025-01-14 11:49:13

你可以使用 ltrim

echo ltrim("../folder/file", "./");

或

echo trim("../folder/file", "./");

you can use ltrim

echo ltrim("../folder/file", "./");

echo trim("../folder/file", "./");

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黒涩兲箜 2025-01-14 11:49:13

php.net/trim 的修剪函数中有一个特殊的语法，允许您指定一个范围，即解释器认为您正在做什么，因为“..”

// trim the ASCII control characters at the beginning and end of $binary
// (from 0 to 31 inclusive)
$clean = trim($binary, "\x00..\x1F");
var_dump($clean);

修剪的第二个参数应该是一个将被删除的字符串，因此您不必放置“.”。两次。

There is a special syntax in the trim function from php.net/trim that allows you to specify a range, which is what the interpreter believes you are doing because of the '..'

// trim the ASCII control characters at the beginning and end of $binary
// (from 0 to 31 inclusive)
$clean = trim($binary, "\x00..\x1F");
var_dump($clean);

The second argument to trim should be a string of characters that would be stripped, so you should not have to put the '.' twice.

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无声无音无过去 2025-01-14 11:49:13

修剪函数的第二个参数指定要删除的字符列表，而不是多字符字符串。该函数将“..”解释为指定字符范围的运算符（如 a..z 或 1..5）。您可以通过多种方式去掉“../”，但一个简单的方法是：

$parts = explode('/', $url);
array_shift($parts);
$url = implode('/', $parts);

The second argument to the trim function specifies a list of characters to be stripped, not a multi-character string. The function interprets '..' as an operator specifying a range of characters (like a..z or 1..5). You can strip out the '../' in a number of ways, but one easy one is this:

$parts = explode('/', $url);
array_shift($parts);
$url = implode('/', $parts);

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绝不放开 2025-01-14 11:49:13

我在 php.net 上的修剪页面的底部评论中找到了这个函数，它似乎可以做你想要的

function trimString($input, $string){
        $input = trim($input);
        $startPattern = "/^($string)+/i";
        $endPattern = "/($string)+$/i";
        return trim(preg_replace($endPattern, '', preg_replace($startPattern,'',$input)));
}

I found this function in bottom comments of the trim page on php.net that seem to do what you want

function trimString($input, $string){
        $input = trim($input);
        $startPattern = "/^($string)+/i";
        $endPattern = "/($string)+$/i";
        return trim(preg_replace($endPattern, '', preg_replace($startPattern,'',$input)));
}

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