当出现“？”时，如何在 Charles Proxy 中设置重写规则包括？
我正在使用 Chales Proxy，到目前为止它对我帮助很大。为了进行测试，我使用重写规则来更改路径参数。只要我不尝试在包含问号的路径上设置重写规则，这效果就很好：
类型：路径
URL示例：/get/article /123456/n/20121208/？
重写规则： /? -> /showAdmin=true/?
我的猜测是问号是一个占位符，我不能将其用作匹配值。我试图逃避它，但也没有成功。
有人知道我该如何解决这个问题吗？关于如何在 Charles 中使用 regEx 的提示也会有所帮助。路径总是相同的。
最好的， 克拉斯
I am using Chales Proxy, and it helped me a lot so far. For testing, I use the rewrite rule to change the Path parameters. This works pretty well, as long as I do not try to set the rewrite rule on a a Path which includes a question mark:
Type: Path
URL sample: /get/article/123456/n/20121208/?
Rewrite rule: /? -> /showAdmin=true/?
My guess is that the questionmark is a placeholder, which I can not use as a match value. I tried to escape it, but it did not work either.
Has anybody got an idea how I can work around it? A hint how to work with regEx in Charles would also help. The path is always the same.
Best,
Klaas
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只是把这个作为答案，因为它让我发疯。为了使用组，您基本上将正则表达式中的内容括在括号组中，如下所示：
whatever/(.*)/(.*)\.html然后在替换字段中，您将将该括号组称为 $1、$2 等等，我认为从左到右。
/whatever/$1/$2.json我相信下面发布的 Stema 应该可以工作，但如果您尝试使用组，这就是您应该如何做的。
Just putting this as an answer because it was driving me nuts. In order to use groups you basically enclose things within the regex in a parentheses group like so:
whatever/(.*)/(.*)\.htmlAnd then in the replace field, you put you refer to that parentheses group as $1, $2 and so on I believe from left to right.
/whatever/$1/$2.jsonI believe what stema posted below should work but in case you were trying to use groups, this is how you would do it.
问号不是占位符，而是量词。因此，
/?表示匹配零个或一个斜杠。快速搜索 文档 说
那么这应该可以工作
$将匹配字符串结尾，如果?也应该在字符串结尾之前匹配，只需将其删除即可。The question mark is not a placeholder, its a quantifier. So,
/?means match zero or one slashes.A quick search for the documentation says
Then this should work
The
$would match the string end, if the?should be matched before the string end also, just remove it.