导航回主 ViewController 解雇ViewControllerAnimated 困境
我有 2 个 ViewController 直接与推送序列连接。我通过调用 [self PerformSegueWithIdentifier:@"segueIdentifier" sender:sender] 从第一个视图控制器导航到第二个视图控制器。在第二个方法中，我有一个绑定到“完成”按钮的 IBAction 方法。按下该按钮基本上应该会导致显示第一个视图控制器（类似于后退按钮）。我设法做到了这一点：
NSArray *viewControllers = self.navigationController.viewControllers;
[self.navigationController popToViewController:[viewControllers
objectAtIndex:0] animated:YES];
我确实尝试通过使用来达到相同的效果：
[self dismissViewControllerAnimated:YES completion:nil];
不管我尝试了什么，尽管这没有完成工作。我试图了解我到底错过了什么，但我无法弄清楚。 missViewControllerAnimated 方法是否仅适用于 Modal segues（这是唯一想到的）。
谢谢
I have 2 ViewControllers directly connected with a push segue. I am navigating from first to second view controller by calling [self performSegueWithIdentifier:@"segueIdentifier" sender:sender]. On the second one I have an IBAction method that is bound to a "Done" button. Pressing that button should basically cause the first view controller to be displayed (sort of a back button). I managed to do that with:
NSArray *viewControllers = self.navigationController.viewControllers;
[self.navigationController popToViewController:[viewControllers
objectAtIndex:0] animated:YES];
I did try to achieve the same effect by using:
[self dismissViewControllerAnimated:YES completion:nil];
No matter what I tried though this didn't do the job. I am trying to understand what exactly am I missing but I can't figure it out. Does dismissViewControllerAnimated method work only with Modal segues ( this is the only thing that came to mind ).
Thank you
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是的，
就是当 UIViewController 以模态方式显示时。
应该做你正在寻求的事情。
所以基本上，在你的第二个 VC 中：
如果你阅读 UIViewController 和 UINavigationController 参考资料，你会省去很多麻烦。两次；）
Yes,
is when a UIViewController is displayed modally.
should do what you are seeking.
So basically, in your second VC:
You will save you a lot of trouble if you read the UIViewController and UINavigationController references. Twice ;)