从已经存在的 nsarray 构建 NSArray

Question

我有一个 NSArray 和来自我的网络服务的 JsonValue 。

myArray = [responseString JSONValue];

这个数组在 NSLog 中给了我这个：

 2012-02-18 18:22:46.338 Test[2758:fb03] myArray: (
            {
            receiver = david;
            sender = sophie;
            message = "test1";
            photo = "****************.jpg";
        },
            {
            receiver = david;
            sender = matt;
            message = "test2";
            photo = "****************.jpg";
        },
            {
            receiver = sophie;
            sender = mike;
            message = "test1";
            photo = "****************.jpg";
        },
            {
            receiver = david;
            sender = ali;
            message = "test1";
            photo = "****************.jpg";
        },
            {
            receiver = mike;
            sender = david;
            message = "test1";
            photo = "****************.jpg";
        },
            {
            receiver = admin;
            sender = david;
            message = "test1";
            photo = "****************.jpg";
        }
    )

我需要创建一个只有 sender = 'David' 的新数组

我尝试这样做：

for(int i=0;i<[myArray count];i++)
   {
    NSDictionary *dict1=[myArray objectAtIndex:i];


       if ( [[dict1 objectForKey:@"sender"] isEqualToString:@"david"]) 


       {

           NSLog(@"YES");


           myNewArray = [[NSArray alloc] initWithObjects:dict1, nil];

            NSLog(@"array %@",myNewArray);
            NSLog(@"count %d",[myNewArray count]);



       }
       else
       {
           NSLog(@"NO");


           myNewArray2 = [[NSArray alloc] initWithObjects:dict1, nil];

            NSLog(@"array2 %@",myNewArray2);
            NSLog(@"count2 %d",[myNewArray2 count]);
       }
   }

这个 myNewArray 给了我这个：

           2012-02-18 18:22:46.341 Test[2758:fb03] myNewArray (
        {
            receiver = mike;
            sender = david;
            message = "test1";
            photo = "****************.jpg";
    }
)
          2012-02-18 18:22:46.341 Test[2758:fb03] myNewArray (
        {
            receiver = admin;
            sender = david;
            message = "test1";
            photo = "****************.jpg";
    }
)

但是我需要一个这样的数组：

2012-02-18 18:22:46.338 Test[2758:fb03] myNewArray: (

        {
            receiver = mike;
            sender = david;
            message = "test1";
            photo = "****************.jpg";
    },
        {
            receiver = admin;
            sender = david;
            message = "test1";
            photo = "****************.jpg";
    }
)

感谢阅读

Answer 1

NSArray 是不可变的，您将需要一个 NSMutableArray。并且您将在每个循环中重新初始化新数组，如果您想保留以前的值，则无法执行此操作。

NSMutableArray *a = [[NSMutableArray alloc] init];

for (int i = 0; i < [myArray count]; i++) {
    NSDictionary *m = [myArray objectAtIndex:i];

    if ([[m objectForKey:@"sender"] isEqualToString:@"david"]) {
        [a addObject:m];
    }
    ...
}

Answer 2

在循环之外声明 myNewArray ，并将其设为 NSMutableArray （它将允许添加新对象），

myNewArray = [[NSMutableArray alloc] array];
for(int i=0;i<[myArray count];i++)
{
    ...
}

然后如果某些条件相等则将对象添加到该数组中

NSLog(@"YES");
[myNewArray addObject:dict1];

Answer 3

有一个更简单的方法。尝试使用 NSArray 的 filteredArrayUsingPredicate: ，其中您的情况中的谓词如下所示：

NSString *attribute = @"sender";
NSString *senderFilter = @"david";
NSPredicate *predicate = [NSPredicate predicateWithFormat:@"%K like %@", attribute, senderFilter];

NSArray *filteredArray = [array filteredArrayUsingPredicate:predicate];

有关谓词的更多详细信息，请尝试 谓词编程指南。