如何在 Ruby on Rails 3 中为每个用户连续编号项目？

发布于 2025-01-07 01:33:07 字数 437 浏览 0 评论 0原文

我对 Ruby on Rails 3 相当陌生，刚刚开始构建一个小应用程序，用户可以在其中管理他们的项目和任务。

显然，所有项目和任务都必须对公众隐藏，并且只能对创建它们的用户可见。

但我发现这很难实现。例如，如果一个用户创建了他的第一个项目，则可以通过 URL /projects/1 访问该项目。如果五秒后另一个用户创建了她的第一个项目，它将出现在 /projects/2 下。

如何为每个用户对项目进行连续编号，始终从 1 或更有意义的数字开始？

另外，我应该如何布局我的资源？

我在想这样的事情：

resources :users do
  resources :projects
  resources :tasks
end

这是一个好的开始方式吗？

原文

I am fairly new to Ruby on Rails 3 and just started to build a little application where Users can manage their Projects and Tasks.

Obviously all Projects and Tasks will have to be hidden from public and should only be visible to the User who created them.

I find this quite difficult to realise though. For example if one User creates his first Project it will be accessible via the URL /projects/1. If another User creates her first Project five seconds later it will appear under /projects/2.

How can I number Projects consecutively for each User, always starting at 1 or something more meaningful?

Also, how should I lay out my resources?

I was thinking of something like this:

resources :users do
  resources :projects
  resources :tasks
end

Is this a good way to start?

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祁梦 2025-01-14 01:33:07

您可以有两个 id，真正隐藏的 id 和公开可见的 consecutive_id。然后，在您的操作中，您必须执行与此类似的操作：

def show
  id = params[:id]

  # instead of
  #   project = Project.find(id)
  # you now do this
  project = Project.where(user_id: current_user.id, consecutive_id: id).first

  # proceed
end

如果您遵循此路径，则必须自己强制执行 id 的顺序。例如，使用 before_create 回调。

You can have two ids, real hidden id and publicly visible consecutive_id. Then, in your actions, you'll have to do something similar to this:

def show
  id = params[:id]

  # instead of
  #   project = Project.find(id)
  # you now do this
  project = Project.where(user_id: current_user.id, consecutive_id: id).first

  # proceed
end

If you follow this path, you'll have to enforce sequentiality of ids yourself. Use before_create callback, for example.

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爱格式化 2025-01-14 01:33:07

首先，我将在 before_create 过滤器中获取最高值，然后生成一个新数字。

class Project < ActiveRecord::Base
  belongs_to :user

  before_create :set_per_user_id

  private
    def set_per_user_id
      val = user.projects.maximum(:document_id)
      self.document_id = val + 1
    end
end

我没有测试代码，但它应该大致是这样工作的。
对 document_id 字段设置一些验证以确保每个用户的唯一性也是一个好主意。

（到目前为止你的路线没问题）

For a start I would get the highest value in a before_create filter and then generate a new number.

class Project < ActiveRecord::Base
  belongs_to :user

  before_create :set_per_user_id

  private
    def set_per_user_id
      val = user.projects.maximum(:document_id)
      self.document_id = val + 1
    end
end

I didn't test the code but it should be roughly working like that.
Setting some validation on the document_id field to ensure uniqueness per user would be a good idea too.

(Your routes are ok so far)

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一身仙ぐ女味 2025-01-14 01:33:07

thorsten 的代码将用于设置项目的 document_id 但您仍然需要重新定义在编辑、更新、显示和销毁控制器操作中加载资源的方式，例如：

def show
  @user = User.find params[:user_id]
  @project = @user.projects.find_by_document_id params[:id]
  render
end

老实说，除非这些 id 是连续的用户是一个巨大的需求，我不建议这样做。它打破了 Rails 约定，如果您尝试使用 cancan 之类的库来授权访问，将会变得很痛苦到资源。

thorsten's code will work for setting the project's document_id but you will still have to redefine how the resource is loaded in the edit, update, show and destroy controller actions, e.g.:

def show
  @user = User.find params[:user_id]
  @project = @user.projects.find_by_document_id params[:id]
  render
end

Honestly, unless having these id's consecutive for the user is a huge requirement, I would not suggest doing it this way. It breaks the rails convention and will make it a pain if you are trying to use libraries like cancan to authorize access to resources.

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