如何获取BIT_FIELD_REF引用的位域的名称？
我想获取从 GENERIC 表示中声明它的字段的名称。我有一个 BIT_FIELD_REF 树，它的 DECL_NAME 为零。例如，
struct {
int a;
unsigned b:1;
} s;
...
if (s.b)
...
对于 sb，我将得到一个 BIT_FIELD_REF，但没有明显的方法来获取“b”，即字段的原始名称。怎么做呢？
I want to get the name of the field with which it was declared from GENERIC representation. I have a BIT_FIELD_REF tree and it's DECL_NAME is zero. For example,
struct {
int a;
unsigned b:1;
} s;
...
if (s.b)
...
For s.b I'll get a BIT_FIELD_REF and there's no obvious way to get the “b”, which is the original name of the field. How to do it?
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尝试从 GDB 调用 debug_c_tree (tree_var) 或调用 debug_tree (tree_var) ，看看是否知道名称。如果是这样，对漂亮的打印机进行逆向工程。
Try
call debug_c_tree (tree_var)orcall debug_tree (tree_var)from GDB, and see if that knows the name. If it does, reverse engineer the pretty-printer.我到底做了什么：调查
tree-dump.c中的内容，我最终了解到已知的位字段的名称来自结构体的 DIE，并且很难跟踪。然后我决定从 BIT_FIELD_REF 参数 0（对结构的引用）类型获取名称，即 RECORD_TYPE ，它存储所有字段的大小和偏移量。
问题是要理解
BIT_FIELD_REF并不引用位本身：它的使用方式类似于BIT_FIELD_REF & INTEGER_CST，其中常量的作用类似于掩码。了解这一点后，我快速计算了偏移量并从类型中获取了名称。What exactly did I do: investigating stuff in
tree-dump.cI ended up understanding that names of the bit fields where they're known were coming from struct's DIEs and were hard to track.Then I decided to get the name from the
BIT_FIELD_REFargument 0 (reference to structure) type, which isRECORD_TYPEand it stores all the fields' sizes and offsets.Problem was to understand that
BIT_FIELD_REFdoesn't reference the bits itself: it is used likeBIT_FIELD_REF & INTEGER_CST, where constant acts like mask. After understanding this, I quickly computed the offsets and got the name from the type.