扫描输入并跳过某些字符
我正在扫描一个文本文件，其中有一个带有几个分隔符的数独板。这就是示例输入的样子。
1 - - | 4 5 6 | - - -
5 7 - | 1 3 b | 6 2 4
4 9 6 | 8 7 2 | 1 5 3
======+=======+======
9 - - | - - - | 4 6 -
6 4 1 | 2 9 7 | 8 3 -
3 8 7 | 5 6 4 | 2 9 -
======+=======+======
7 - - | - - - | 5 4 8
8 r 4 | 9 1 5 | 3 7 2
2 3 5 | 7 4 $ | 9 1 6
其中有“|”的地方作为边框，====+====+==== 作为分隔线。我编写此代码是为了忽略 |和 ===+====+=== 但它跳过了这部分代码并将它们声明为无效字符并在其中添加 0
public static int [][] createBoard(Scanner input){
int[][] nSudokuBoard = new int[9][9];
for (rows = 0; rows < 9; rows++){
for (columns = 0; columns < 9; columns++){
if(input.hasNext()){
if(input.hasNextInt()){
int number = input.nextInt();
nSudokuBoard[rows][columns] = number;
}//end if int
else if(input.hasNext("-")){
input.next();
nSudokuBoard[rows][columns] = 0;
System.out.print("Hyphen Found \n");
}//end if hyphen
else if(input.hasNext("|")){
System.out.print("border found \n");
input.next();
}// end if border
else if(input.hasNext("======+=======+======")){
System.out.print("equal row found \n");
input.next();
}// end if equal row
else {
System.out.print("Invalid character detected at... \n Row: " + rows +" Column: " + columns +"\n");
System.out.print("Invalid character(s) replaced with a '0'. \n" );
input.next();
}//end else
}//end reading file
}//end column for loop
}//end row for looop
return nSudokuBoard;
}//end of createBoard
我与导师讨论过，但我不记得他关于如何进行的建议解决这个问题。
I'm scanning a text file that has a sudoku board with a few separators. this is what a sample input would look like.
1 - - | 4 5 6 | - - -
5 7 - | 1 3 b | 6 2 4
4 9 6 | 8 7 2 | 1 5 3
======+=======+======
9 - - | - - - | 4 6 -
6 4 1 | 2 9 7 | 8 3 -
3 8 7 | 5 6 4 | 2 9 -
======+=======+======
7 - - | - - - | 5 4 8
8 r 4 | 9 1 5 | 3 7 2
2 3 5 | 7 4 $ | 9 1 6
where it has "|" as borders and =====+====+==== as dividers. I made this code to ignore the | and ====+===+=== but it's skipping that part of the code and declaring them as invalid characters and adding 0's in there place
public static int [][] createBoard(Scanner input){
int[][] nSudokuBoard = new int[9][9];
for (rows = 0; rows < 9; rows++){
for (columns = 0; columns < 9; columns++){
if(input.hasNext()){
if(input.hasNextInt()){
int number = input.nextInt();
nSudokuBoard[rows][columns] = number;
}//end if int
else if(input.hasNext("-")){
input.next();
nSudokuBoard[rows][columns] = 0;
System.out.print("Hyphen Found \n");
}//end if hyphen
else if(input.hasNext("|")){
System.out.print("border found \n");
input.next();
}// end if border
else if(input.hasNext("======+=======+======")){
System.out.print("equal row found \n");
input.next();
}// end if equal row
else {
System.out.print("Invalid character detected at... \n Row: " + rows +" Column: " + columns +"\n");
System.out.print("Invalid character(s) replaced with a '0'. \n" );
input.next();
}//end else
}//end reading file
}//end column for loop
}//end row for looop
return nSudokuBoard;
}//end of createBoard
I talked it over with a tutor but i don't remember his suggestion on how to fix this.
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评论（2）
即使您正在使用边框或分隔线，您的循环也会增加行计数器和列计数器。因此，即使您解决了其他问题（如前面的答案中所述），您也将在阅读所有输入之前完成填充矩阵。您需要修改代码，以便仅在消耗完整数或短划线后有条件地推进行计数器和列计数器。这意味着删除 for 循环，将第一个 if(input.hasNext()) 更改为 while，并添加 rows++ 和 columns++ 在您使用整数或短划线并为 nSudokuBoard[rows][columns] 设置值的位置。您还需要逻辑来确定何时增加行以及何时将列设置回0。
另外，从风格上来说，您应该将 rows 重命名为 row，将 columns 重命名为 column。
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hasNext的 String 参数被视为正则表达式。您需要转义特殊字符：http://ideone.com/43j7R
The String parameter to
hasNextis treated as a regular expression. You need to escape special characters:http://ideone.com/43j7R