从 C# 运行 .bat 文件
我面临一个奇怪的问题，我有一个 .bat 文件，其中包含用于重命名文件的代码，当我手动打开 .bat 文件时，它会执行上面写的操作，即重命名文件，但是当我尝试打开时它以 C# 方式编程，它不执行任何操作，它只是打开文件并且不编译它写入的内容。我输入了该代码：
Process.Start(@"file.bat");
我也知道如果您在cmd中输入路径并按回车键，它将打开文件并编译它，所以我写了：
ProcessStartInfo psi3 = new ProcessStartInfo("cmd", "/c " + '"'+"D:\\my Work\\My Soft\\CA Delete\\CA Delete\\bin\\Debug\\file.bat"+'"');
Process p3 = Process.Start(psi3);
p3.WaitForExit()
但仍然是同样的问题：文件正在打开，但从未执行其写入的操作进入其中。
编辑：[我想出了为什么]
我拍摄了应该运行 .bat 文件的 CMD 窗口的快照，但我得到了错误：
ERROR : THE FILE SPECIFIED COULD NOT BE FOUND
但是怎么办？当我手动运行 .bat 文件时，它工作正常！
i am facing a strange issue , i have a .bat file which contains a code for renaming a file , when i open the .bat file manually it does what it is written on it which is renaming a file , but when i try to open it programtically from C# , it doesnt do anything , it jsut open the file and do not compile what it is written into . i typed that code :
Process.Start(@"file.bat");
I also knew if you typed the path into cmd and pressed enter it will open the file and compile it , so i wrote that :
ProcessStartInfo psi3 = new ProcessStartInfo("cmd", "/c " + '"'+"D:\\my Work\\My Soft\\CA Delete\\CA Delete\\bin\\Debug\\file.bat"+'"');
Process p3 = Process.Start(psi3);
p3.WaitForExit()
But still the same issue : the file is being opened but never does what it is written into it.
EDIT : [I Figured why]
I took a snap shot of the CMD windows that should run the .bat file and i got ERROR :
ERROR : THE FILE SPECIFIED COULD NOT BE FOUND
but how ? when i run the .bat file manually it works FINE!!!
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你可以这样尝试。 ProcessStartInfo
you may try like this. ProcessStartInfo
您可能需要额外的管理员权限才能执行批处理文件中的预期内容。如果是这样，请使用 Process.Start() 的替代版本：
You may be requiring additional admin previleges to execute what is intended in the Batch file. If so, use the alternative version of Process.Start():
将批处理文件的第一行设置为：
Pushd %~dp1
这将设置批处理文件的工作目录。
马丁
Make the first line of the batch file this:
pushd %~dp1
This will set the batch files working directory.
martyn
这应该对您有用：
myBatchFileName是 .bat 文件的实际名称......This should work for you:
myBatchFileNameis the actual name of .bat file.....