UTF-8 和 ISO 8859-1 之间的转换:
我在SO中找到了以下代码。这真的有效吗?
String xml = new String("áéíóúñ");
byte[] latin1 = xml.getBytes("UTF-8");
byte[] utf8 = new String(latin1, "ISO-8859-1").getBytes("UTF-8");
我的意思是,第二行中的 latin1 是 UTF-8 编码的,但第三行中是 ISO-8859-1 编码的?这能行得通吗?
并不是说我不想批评引用的代码,我只是感到困惑,因为我遇到了一些非常相似的遗留代码,它们似乎有效,但我无法解释原因。
编辑:我想在原来的 帖子 中,第 2 行中的“UTF-8”只是一个拼写错误。但我不确定...
编辑2:在我最初发布后,有人编辑了上面的代码并将第二行更改为 byte[] latin1 = xml.getBytes("ISO-8859-1");
。我不知道是谁干的,也不知道他为什么这么做,但显然这件事搞砸了。向所有看到错误版本代码的人表示抱歉。我不知道是谁编辑的。上面的代码现在是正确的。
I found the following code in SO. Does this really work?
String xml = new String("áéíóúñ");
byte[] latin1 = xml.getBytes("UTF-8");
byte[] utf8 = new String(latin1, "ISO-8859-1").getBytes("UTF-8");
I mean, latin1
is UTF-8-encoded in the second line, but read als ISO-8859-1-encoded in the third? Can this ever work?
Not that I did not want to criticize the cited code, I am just confused since I ran into some legacy code that is very similar, that seems to work, and I cannot explain why.
EDIT: I guess in the original post, "UTF-8" in line 2 was just a TYPO. But I am not sure ...
EDIT2: After my initial posting, someone edited the code above and changed the 2nd line to byte[] latin1 = xml.getBytes("ISO-8859-1");
. I don't know who did that and why he did it, but clearly this messed up pretty much. Sorry to all who saw the wrong version of the code. I don't know who edited it. The code above is correct now.
如果你对这篇内容有疑问,欢迎到本站社区发帖提问 参与讨论,获取更多帮助,或者扫码二维码加入 Web 技术交流群。

绑定邮箱获取回复消息
由于您还没有绑定你的真实邮箱,如果其他用户或者作者回复了您的评论,将不能在第一时间通知您!
发布评论
评论(2)
getBytes(Charset charset)
生成使用charset
编码的字节数组,因此 latin1 是 UTF-8 编码的。将 System.out.println(latin1.length); 作为第三行,它会告诉您字节数组长度是 12。这意味着它确实是 UTF-8 编码的。
new String(latin1, "ISO-8859-1")
不正确,因为 latin1 是 UTF-8 编码的,并且您告诉将其解析为 ISO-8859-1。这就是为什么它会生成一个由 12 个垃圾符号组成的字符串:àñààñoñ
。当您使用 UTF-8 编码从
à à à àñ 获取字节时,它会生成一个 24 长字节数组。
我希望现在一切都清楚了。
getBytes(Charset charset)
results in a byte array encoded using thecharset
, so latin1 is UTF-8 encoded.Put
System.out.println(latin1.length);
as the third line and it will tell you that byte array length is 12. This means that it is really UTF-8 encoded.new String(latin1, "ISO-8859-1")
is incorrect because latin1 is UTF-8 encoded and you're telling to parse it as ISO-8859-1. That's why it produces a String made of 12 symbols of garbage:áéÃóúñ
.When you're getting bytes from
áéÃóúñ
using UTF-8 encoding it results in a 24 long byte array.I hope everything is clear now.
这些字符都存在于两种字符编码中。只是 UTF-8 和 ISO-8859-1 使用超出 ASCII 范围的每个字符的不同字节表示形式。
如果您使用了 UTF-8 中存在但 ISO-8859-1 中不存在的字符,那么它当然会失败。
Those characters are present in the both character encodings. It's just that UTF-8 and ISO-8859-1 uses each different byte representations of each character beyond the ASCII range.
If you used a character which is present in UTF-8, but not in ISO-8859-1, then it will of course fail.