iOS：以编程方式添加不同的 tableviewcell

Question

我想知道根据 API 中的数据创建行并将行添加到 uitableview 的最佳方法是什么。从 API 返回的数据如下所示。有些字段需要是标准文本，有些字段需要密码文本字段，有些字段需要数字字段，有些字段需要是开关和日期选择器字段。

我猜我需要将每个单元格的一个字段添加到我的 UITableView 中才能拥有单元格基础。然后，根据我当时添加的单元格，我将检索该单元格并将其添加到表中。

我将如何跟踪数据？当用户提交信息时，我如何知道哪个字段是哪个？

API 返回的字段将取决于他们在我们网站中启用的设置。并且顺序会根据他们设置的 sort_order 而有所不同。

"data": [
{
"field_name": "location_id",
"display_name": "Home Location",
"page_cust": "O",
"sort_order": "10"
},
{
"field_name": "first_name",
"display_name": "First Name1",
"page_cust": "R",
"sort_order": "20"
},
{
"field_name": "middle_name",
"display_name": "Middle Name",
"page_cust": "O",
"sort_order": "25"
},
{
"field_name": "last_name",
"display_name": "Last Name1",
"page_cust": "R",
"sort_order": "30"
},
{
"field_name": "address1",
"display_name": "Address",
"page_cust": "O",
"sort_order": "40"
},
{
"field_name": "address2",
"display_name": "Address 2",
"page_cust": "O",
"sort_order": "45"
},
{
"field_name": "city",
"display_name": "City",
"page_cust": "O",
"sort_order": "50"
},
{
"field_name": "state",
"display_name": "State",
"page_cust": "O",
"sort_order": "60"
},
{
"field_name": "zip",
"display_name": "Zip Code",
"page_cust": "O",
"sort_order": "70"
},
{
"field_name": "day_phone",
"display_name": "Daytime Phone",
"page_cust": "O",
"sort_order": "80"
},
{
"field_name": "night_phone",
"display_name": "Evening Phone",
"page_cust": "O",
"sort_order": "90"
},
{
"field_name": "cell_phone",
"display_name": "Cell Phone",
"page_cust": "O",
"sort_order": "100"
},
{
"field_name": "email",
"display_name": "eMail",
"page_cust": "O",
"sort_order": "110"
},
{
"field_name": "login",
"display_name": "Login",
"page_cust": "O",
"sort_order": "120"
},
{
"field_name": "password",
"display_name": "Password",
"page_cust": "O",
"sort_order": "130"
},
{
"field_name": "lead_id",
"display_name": "Heard Via?",
"page_cust": "O",
"sort_order": "140"
},
{
"field_name": "contact_okay",
"display_name": "Contact Okay",
"page_cust": "O",
"sort_order": "170"
},
{
"field_name": "call_okay",
"display_name": "Call Okay",
"page_cust": "O",
"sort_order": "180"
},
{
"field_name": "email_okay",
"display_name": "E-mail Okay",
"page_cust": "O",
"sort_order": "190"
},
{
"field_name": "mail_okay",
"display_name": "Mail Okay",
"page_cust": "O",
"sort_order": "200"
},
{
"field_name": "payment_type_id",
"display_name": "Payment Method",
"page_cust": "O",
"sort_order": "210"
},
{
"field_name": "employer",
"display_name": "Company",
"page_cust": "O",
"sort_order": "260"
},
{
"field_name": "occupation",
"display_name": "Occupation",
"page_cust": "O",
"sort_order": "270"
},
{
"field_name": "birth_date",
"display_name": "Birth Date",
"page_cust": "O",
"sort_order": "280"
},
{
"field_name": "gender",
"display_name": "Gender",
"page_cust": "O",
"sort_order": "290"
},
{
"field_name": "status_id",
"display_name": "Status",
"page_cust": "O",
"sort_order": "340"
},
{
"field_name": "allow_login",
"display_name": "Allow to Log In",
"page_cust": "O",
"sort_order": "350"
},
{
"field_name": "customer_type_id",
"display_name": "Customer Type",
"page_cust": "O",
"sort_order": "360"
},
{
"field_name": "rep_id",
"display_name": "Assigned To",
"page_cust": "O",
"sort_order": "370"
},
{
"field_name": "account",
"display_name": "Account Number",
"page_cust": "O",
"sort_order": "380"
},
{
"field_name": "needs",
"display_name": "Special Needs",
"page_cust": "O",
"sort_order": "390"
}
]

Answer 1

您正在使用网络服务。根据用户设置，您会以某种特定顺序返回由特定字段组成的 JSON 响应。

您已经解析了 JSON，并且您得到了一本字典，其中包含一个字典数组的一个键 ("data")，对吗？

最简单的方法是将这些字典存储在可变数组 NSMutableArray 中。
您知道哪个单元格是哪个对象，因为数据源将被要求提供特定行号处的单元格。第 0 行的单元格将显示数组中第一个字典的字段，依此类推。

NSDictionary *dictAtRow0 = [mySourceArray objectAtIndex:0];

如果您想知道如何知道字典中是否存在特定字段，请测试字典中是否存在相应的键，如下所示：

if([[dictAtRow0 allKeys] containsObject:@"field_name"]) {
    // here you know the dictionary has an entry for the key "field_name"
}

也可以根据“sort_order”键的值对数组内容重新排序。尽管网络服务似乎遵循该顺序，但您可能希望以编程方式执行此操作。我建议是在填充源数组之前执行此操作：

// you parsed JSON and get the dictionary
NSArray *sortedArray = [[mainDict objectForKey:@"data"] sortedArrayUsingComparator: ^(id a, id b) {
    NSNumber *first = [NSNumber numberWithInteger:[[a objectForKey:@"sort_order"] integerValue]];
    NSNumber *second = [NSNumber numberWithInteger:[[b objectForKey:@"sort_order"] integerValue]];
    return [first compare:second];
}];
mySourceArray = [[NSMutableArray alloc] initWithArray:sortedArray];

我没有测试该代码，比较器可能有错误，但您明白了。