使用 ColdFusion 循环数组

发布于 2025-01-05 04:54:40 字数 677 浏览 0 评论 0原文

我有一个购物车数组，其中有一个变量来告诉我该产品是否是配件，这将是或否。我需要遍历购物车并找出以下信息：

购物车是否仅包含配件；做任何事。
如果购物车仅为产品；做任何事。
购物车是否有产品和配件；做任何事。

我一直在尝试这样做：

<cfloop index="i" from="1" to="#arrayLen(session.mycart)#">
  <cfif session.mycart[i].accs EQ "yes">
    <cfset accPresent = "yes">
  </cfif>
  <cfif session.mycart[i].accs EQ "no">
    <cfset prodpresent = "yes">
  </cfif>
</cfloop>

<cfif accPresent EQ "yes" and prodPresent EQ "no">
  <cfset  bothPresent EQ "yes">
</cfif>

由于未找到 accPresent，这会失败，我认为这是因为循环一次经过一个，并且一旦找到非配件产品，accs 就不等于 yes。实现我想要做的事情的最佳方法是什么？

原文

I have a shopping cart array, which has a variable to tell me if the product is an accessory or not, this will be either yes or no. I need to loop through the cart and find out the following:

If the cart contains accessories only; do whatever.
If the cart is products only; do whatever.
If the cart has products and accessories; do whatever.

I have been trying this:

<cfloop index="i" from="1" to="#arrayLen(session.mycart)#">
  <cfif session.mycart[i].accs EQ "yes">
    <cfset accPresent = "yes">
  </cfif>
  <cfif session.mycart[i].accs EQ "no">
    <cfset prodpresent = "yes">
  </cfif>
</cfloop>

<cfif accPresent EQ "yes" and prodPresent EQ "no">
  <cfset  bothPresent EQ "yes">
</cfif>

This falls down as accPresent is not found, this i think is due to the fact the loop goes through one at a time and the accs is not equal to yes once it find a non accessory product. What's the best way to achieve what I'm trying to do?

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-柠檬树下少年和吉他 2025-01-12 04:54:40

这样做

<cfset accPresent = "no" />
<cfset prodPresent = "no" />
<cfloop index="i" from="1" to="#arrayLen(session.mycart)#">
    <cfif session.mycart[i].accs EQ "yes">
        <cfset accPresent = "yes">
    </cfif>
    <cfif session.mycart[i].accs EQ "no">
        <cfset prodpresent = "yes">
    </cfif>
</cfloop>

<cfif accPresent EQ "yes" and prodPresent EQ "no">
    <cfset  bothPresent EQ "yes">
</cfif>

Do this

<cfset accPresent = "no" />
<cfset prodPresent = "no" />
<cfloop index="i" from="1" to="#arrayLen(session.mycart)#">
    <cfif session.mycart[i].accs EQ "yes">
        <cfset accPresent = "yes">
    </cfif>
    <cfif session.mycart[i].accs EQ "no">
        <cfset prodpresent = "yes">
    </cfif>
</cfloop>

<cfif accPresent EQ "yes" and prodPresent EQ "no">
    <cfset  bothPresent EQ "yes">
</cfif>

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柳若烟 2025-01-12 04:54:40

Jason，

您的第三条语句假设 AccPresent 和 ProdPresent 都存在。您是否先创建了它们并给了它们默认值？试试这个：

<cfparam name="accPresent" default="no"/>
<cfparam name="prodPresent" default="no"/>
<cfloop index="i" from="1" to="#arrayLen(session.mycart)#">
<cfif session.mycart[i].accs EQ "yes">
<cfset accPresent = "yes">
</cfif>
<cfif session.mycart[i].accs EQ "no">
<cfset prodpresent = "yes">
</cfif>
</cfloop>    
<cfif accPresent EQ "yes" and prodPresent EQ "no">
<cfset  bothPresent EQ "yes">
</cfif>

当然，这假设默认情况下每个都应设置为“否”。

Jason,

Your 3rd statement assumes that AccPresent and ProdPresent will both exist. Did you create them first and give them default values? Try this:

<cfparam name="accPresent" default="no"/>
<cfparam name="prodPresent" default="no"/>
<cfloop index="i" from="1" to="#arrayLen(session.mycart)#">
<cfif session.mycart[i].accs EQ "yes">
<cfset accPresent = "yes">
</cfif>
<cfif session.mycart[i].accs EQ "no">
<cfset prodpresent = "yes">
</cfif>
</cfloop>    
<cfif accPresent EQ "yes" and prodPresent EQ "no">
<cfset  bothPresent EQ "yes">
</cfif>

This assumes of course that each of these should be set to "no" by default.

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烟凡古楼 2025-01-12 04:54:40

在 ColdFusion 8 及更高版本中，可以直接使用数组

<cfloop index="i" array="#session.mycart#">
  <cfif i.accs EQ "yes">
    <cfset accPresent = "yes">
  </cfif>
  <cfif i.accs EQ "no">
    <cfset prodpresent = "yes">
  </cfif>
</cfloop>

<cfif accPresent EQ "yes" and prodPresent EQ "no">
  <cfset  bothPresent EQ "yes">
</cfif>

注意：i 指的是包含数据的结构，而不是数据的位置

< a href="http://livedocs.adobe.com/coldfusion/8/htmldocs/help.html?content=Tags_j-l_15.html" rel="nofollow">http://livedocs.adobe.com/coldfusion/8/htmldocs/help.html?content=Tags_j-l_15.html

In versions of ColdFusion 8 and higher, a <cfloop> can use an array directly

<cfloop index="i" array="#session.mycart#">
  <cfif i.accs EQ "yes">
    <cfset accPresent = "yes">
  </cfif>
  <cfif i.accs EQ "no">
    <cfset prodpresent = "yes">
  </cfif>
</cfloop>

<cfif accPresent EQ "yes" and prodPresent EQ "no">
  <cfset  bothPresent EQ "yes">
</cfif>

Note: That i refers to the struct containing the data, not position of the data

http://livedocs.adobe.com/coldfusion/8/htmldocs/help.html?content=Tags_j-l_15.html

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荭秂 2025-01-12 04:54:40

在 CF 10（或 Railo 4）中，可以使用 cfscript 和 Underscore.cfc 库< /a>：

_ = new Underscore();

myCart = duplicate(session.myCart);

accPresent = _.any(myCart, function(val) {
    return val.accs;
});

prodPresent = _.any(myCart, function(val) {
    return !val.accs;
});

bothPresent = accPresent && prodPresent;

_.find() 的伟大之处在于，一旦迭代器函数返回 true，它就会停止，因此您不必迭代数组中的每个元素。

注意：建议在访问共享范围变量时使用 duplcate() 以防止死锁。

（免责声明：我写了Underscore.cfc）

In CF 10 (or Railo 4), this can be done more elegantly using cfscript and the Underscore.cfc library:

_ = new Underscore();

myCart = duplicate(session.myCart);

accPresent = _.any(myCart, function(val) {
    return val.accs;
});

prodPresent = _.any(myCart, function(val) {
    return !val.accs;
});

bothPresent = accPresent && prodPresent;

The great thing about _.find() is that it stops as soon as the iterator function returns true, so you don't have to iterate over every single element in the array.

Note: Using duplcate() is recommended when accessing shared-scope variables in order to prevent deadlocks.

(Disclaimer: I wrote Underscore.cfc)

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