Greasemonkey：使用 XPath 从远程 XML 文档获取元素

发布于 2025-01-05 03:39:41 字数 1018 浏览 2 评论 0原文

我试图用 Greasemonkey 脚本做的是：

读取一些远程 XML 文档；
将其转换为XML对象；
然后使用XPath获取其中的元素。

getElementsByTagName(TagName) 方法可以很好地处理我的 XML 对象，但 evaluate("XPath expression") 却不能。有什么建议吗？请参阅下面的代码：

GM_xmlhttpRequest({
   method: "GET",
   url: "http://www.someserver.com/atom.xml",
   onload: function(response) {
      if (!response.responseXML) { 
         var xmlDoc = new DOMParser().parseFromString(response.responseText, "application/xml"); 
      }

// this section works fine and returns the data of the first <entry>..</entry> 
      var snapEntries = xmlDoc.getElementsByTagName("entry");
          alert (snapEntries[0].data);

// this section doesn't work for unknown reason and returns nothing         
      var snapEntriesXpath = xmlDoc.evaluate("//entry", xmlDoc, null, XPathResult.UNORDERED_NODE_SNAPSHOT_TYPE, null);
          alert (snapEntriesXpath.snapshotItem(0).data);
    }
});

原文

What Im trying to do with my Greasemonkey script is:

to read some distant XML document;
convert it into XML object;
and then use XPath to get the elements inside of it.

The getElementsByTagName(TagName) method works fine with my XML-object, but evaluate("XPath expression") doesn't. Any suggestions? See the code below:

GM_xmlhttpRequest({
   method: "GET",
   url: "http://www.someserver.com/atom.xml",
   onload: function(response) {
      if (!response.responseXML) { 
         var xmlDoc = new DOMParser().parseFromString(response.responseText, "application/xml"); 
      }

// this section works fine and returns the data of the first <entry>..</entry> 
      var snapEntries = xmlDoc.getElementsByTagName("entry");
          alert (snapEntries[0].data);

// this section doesn't work for unknown reason and returns nothing         
      var snapEntriesXpath = xmlDoc.evaluate("//entry", xmlDoc, null, XPathResult.UNORDERED_NODE_SNAPSHOT_TYPE, null);
          alert (snapEntriesXpath.snapshotItem(0).data);
    }
});

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假情假意假温柔 2025-01-12 03:39:41

IIRC，.data 属性不会出现在每种搜索中。

您可能需要使用：

var snapEntriesXpath = xmlDoc.evaluate (
    "//entry//text()", xmlDoc, null, XPathResult.UNORDERED_NODE_SNAPSHOT_TYPE, null
);

但可能还有其他几个问题在起作用。如果这不起作用，(1) 链接到确切的 XML 文件；如有必要，请使用 pastebin.com。 (2) 报告 Firefox 错误控制台 (CtrlShiftJ) 报告的内容。

IIRC, the .data attribute won't be present for every kind of search.

You probably need to use:

var snapEntriesXpath = xmlDoc.evaluate (
    "//entry//text()", xmlDoc, null, XPathResult.UNORDERED_NODE_SNAPSHOT_TYPE, null
);

But several other issues could be at play. If that doesn't do it, (1) link to the exact XML file; use pastebin.com if necessary. (2) Report what Firefox's error console (CtrlShiftJ) reports.

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