精灵运动的 MultiTouch 控制 - cocos2d

Question

我已经处理这个问题有一段时间了。 我想做的是通过屏幕左侧或右侧的触摸来控制 CCSprite 的右/左移动。

如果您在每次触摸后抬起手指，那么这样做就没有问题。但我想要的最好用一个例子来描述： 玩家触摸屏幕的左侧，精灵就会向左移动。现在玩家（仍然触摸左侧）触摸右侧......精灵现在应该向右移动。现在玩家的一根手指在左侧，一根手指在右侧，如果他现在将触摸从右侧移开，精灵应该再次向左侧移动。

这就是我现在所拥有的：

-(void)ccTouchesBegan:(NSSet *)touches withEvent:(UIEvent *)event {
    NSSet *allTouches = [event allTouches];
    UITouch * touch = [[allTouches allObjects] objectAtIndex:0];
    CGPoint location = [touch locationInView: [touch view]];
    location = [[CCDirector sharedDirector] convertToGL:location];

    if (location.x < 240) {
        [player walk:kkMoveLeft];
    } else if (location.x > 240) {
        [player walk:kkMoveRight];
    }

    //Swipe Detection Part 1
    firstTouch = location;
}

-(void) ccTouchesEnded:(NSSet *)touches withEvent:(UIEvent *)event {
    NSSet *allTouches = [event allTouches];
    UITouch * touch = [[allTouches allObjects] objectAtIndex:0];
    CGPoint location = [touch locationInView: [touch view]];
    location = [[CCDirector sharedDirector] convertToGL:location];

    //Swipe Detection Part 2
    lastTouch = location;

    float swipeLength = ccpDistance(firstTouch, lastTouch);

    if (firstTouch.y < lastTouch.y && swipeLength > 60) {
        [player jump:kkJumpUp];
    } else if (firstTouch.y > lastTouch.y && swipeLength > 60){
        [player jump:kkJumpDown];
    }

    [player endWalk];

}

如果有人能告诉我如何解决这个问题，我将不胜感激。谢谢 。

更新我的解决方案：

//1. Enable multitouch in the appDelegate
[glView setMultipleTouchEnabled:YES];

//2. Create an Array to keep track of active touches
touchArray = [[NSMutableArray alloc] init];

//3. Touch Methods
-(void)ccTouchesBegan:(NSSet *)touches withEvent:(UIEvent *)event {

    for (UITouch *touch in touches) {
        if (![touchArray containsObject:touch]) {
            [touchArray addObject:touch];
            CGPoint location = [touch locationInView:[touch view]];
            location = [[CCDirector sharedDirector] convertToGL:location];
            CCLOG(@"start: %f", location.x);
            if (location.x < 240) {
                [player walk:kkMoveLeft];
            } else if (location.x > 240) {
                [player walk:kkMoveRight];
            }
        }
    }

}

-(void) ccTouchesEnded:(NSSet *)touches withEvent:(UIEvent *)event {

    for (UITouch *touch in touches) {
        [touchArray removeObject:touch];
        CGPoint location = [touch locationInView:[touch view]];
        location = [[CCDirector sharedDirector] convertToGL:location];
        CCLOG(@"end: %f", location.x);
    }

    for (UITouch *touch in touchArray) {
        CGPoint location = [touch locationInView:[touch view]];
        location = [[CCDirector sharedDirector] convertToGL:location];
        CCLOG(@"still: %f", location.x);
        if (location.x < 240) {
            [player walk:kkMoveLeft];
        } else if (location.x > 240) {
            [player walk:kkMoveRight];
        }
    }


    if ([touchArray count] == 0) {
        [player endWalk];
    }

}

Answer 1

如果我正确理解您的问题，您应该做的是：

1. 在 ccTouchesEnded 中，而不是简单地调用 endWalk，检查是否仍然存在任何触摸（以这样做，您可以在 ccTouchesEnded 中迭代 allTouches);

2. 在适当的情况下（即，触摸仍在激活播放器），调用 startWalk。

3. 如果没有触摸，则调用endWalk。

该代码与您在 ccTouchesBegan 中的代码类似，只是您进行迭代（我不确定 allTouches 在 TouchesEnded 的索引 0 处包含什么）。

旧答案：

你没有说任何关于你现在如何处理触摸的事情。无论如何，正确的方法是定义 ccTouches* 方法（相对于 ccTouch*），其中 * 可以是：Began、已移动，已结束。

-(void)tccTouchesBegan:(NSSet *)touches withEvent:(UIEvent *)event {
UITouch *touch = [[event allTouches] anyObject];
CGPoint location = [touch locationInView:[touch view]];
location = [[CCDirector sharedDirector] convertToGL:location];
    ...
}
-(void)ccTouchesMoved:(NSSet *)touches withEvent:(UIEvent *)event {
  ...
}
-(void)ccTouchesEnded:(NSSet *)touches withEvent:(UIEvent *)event {
  ...
}

请记住，touchesBegan 会在检测到每个新触摸时触发。因此，如果您想了解当前活动的所有触摸的状态，则必须使用 allTouches。

还可以看看 来自 iphonesdk 的这篇文章，我发现它对语义很有洞察力这些方法中的触摸次数。