十六进制偏移量
我正在查看一些十六进制代码，有人告诉我查看偏移量：0x830880EC 存储为小端，但这意味着什么？浏览 HxD Workshop 中列出的偏移量，我没有看到这样的内容，我很确定 0x 只是某种形式的前缀或其他东西，但我不知道它意味着什么。有人可以帮助我吗？提前致谢！
I was looking at some hexadecimal code and someone told me to look at offset : 0x830880EC
stored as little endian, but what does this mean? Browsing through the offsets listed in HxD Workshop, I see nothing like this, I am pretty sure that 0x is just some form of prefix or something, but I do not know what it means. Could someone help me? Thanks in advance!
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在HXD中，您将需要使用GoTo函数，然后跳转到该地址，0x只是指定十六进制数的前缀，只有在实际编程时才真正需要，或者澄清您正在共享十六进制数。另外，根据您所查看的内容，HxD 中的地址可能会有所不同。例如，在 Xbox 360 上进行改装时，游戏的内存从 0x82000000 开始，但在 HxD 中，该地址仅为 0x00000000。因此，根据您的起始地址，该值可能会发生变化。希望这有帮助！
In HXD you will want to use the GoTo function, then jump to that address, the 0x is just a prefix designating a hexadecimal number, it's only really necessary when actually programming, or to clarify that you are sharing a hex number. Also depending on what you are looking at, the address might be different in HxD. For example, when modding on the xbox 360, a game's memory starts at 0x82000000, but in HxD this address would just be 0x00000000. So based on your starting address, the value could change. Hopefully this helps!
您可能想要搜索值 0x830880EC 并获取相应的偏移量。 0x 是添加到十六进制数的前缀，因此实际的十六进制数是 830880EC。您可以搜索该数字，如果没有找到它，请在更改字节顺序（字节顺序）后尝试。
如果我们假设 83 08 80 EC 是大端，那么 EC 80 08 83 将是小端，反之亦然。一旦找到该值，您应该能够计算相应的偏移量。
You probably want to search for the value 0x830880EC and fetch corresponding offset. 0x is prefix added to hexadecimal number so actual hexadecimal number is 830880EC. You can search for this number and if you do not find it try after changing endianness (byte order).
If we suppose that 83 08 80 EC is big endian then EC 80 08 83 would be little endian or vice-versa. Once you find the value you should be able to calculate corresponding offset.