使用 C++ 获取系统硬盘使用情况
我想知道在非托管 C++ 代码中这是否可能？
我正在编写一个程序来显示系统上当前的 CPU 使用率，但我观察到，在一些较新的台式机上，当正在进行一些长时间的硬盘驱动器操作时（例如，来自后台备份过程），CPU 使用率保持非常低（低于10%）但系统使用起来有点慢。所以我想在我的程序中添加系统范围内当前 HDD 使用情况，我只是不确定要使用什么 API。
I was wondering if such is possible in the unmanaged C++ code?
I'm writing a program that shows the current CPU usage on the system, but I observed that on some newer desktops when some lengthy hard drive operation is in process (say, like from a background backup process) the CPU usage stays very low (less than 10%) but the system is somewhat slow to use. So I was thinking to add to my program the current HDD usage on a system-wide scale, I'm just not sure what API to use for that.
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您正在寻找“% Disk Time”性能计数器。这表示磁盘忙于处理请求的（平均）时间比例。如果接近 100%，则 CPU 可能会长时间等待 I/O 完成。
另一个选项是“当前磁盘队列长度”。这表明有多少请求处于待处理状态，这反过来又是对超额操作（已发出的操作 - 已完成的操作）的度量。如果队列中的挂起操作为零，则 CPU 不会等待磁盘；如果有很多，那么CPU就没有任何作用。
当然，如果存在低优先级 CPU 循环线程，那么当高优先级线程等待 I/O 时，这些线程仍将运行。 Windows 不会因为磁盘繁忙而浪费 CPU 时间。
You're looking for the "% Disk Time" performance counter. That indicates the (averaged) fraction of time that the disk is busy servicing requests. If it's close to 100%, then the CPU will probably be waiting a lot for I/O's to complete.
Another option is the "Current Disk Queue Length". That indicates how many requests are pending, which in turn is a measure of the excess operations (operations issued - operations completed). If there are zero pending operations in the queue, the CPU is not waiting for the disk; if there are tons, then the CPU has nothing to do.
Of course, if there are low-priority CPU-cound threads, then those will still run while the higher-priority threads are waiting for I/O. Windows won't waste CPU time just because the disk is busy.