在处理完整字符串之前释放/删除 strtok_r 指针？

发布于 2025-01-04 07:03:04 字数 636 浏览 1 评论 0原文

当尝试删除/释放字符 ptr 而没有被 strtok_r 完全处理时，它给我堆栈跟踪错误。

我知道，如果不通过 strtok_r 函数完成整个字符串分离过程，就无法以常规方式释放/删除 strtok_r char ptr。

谁能告诉我如何在 strtok_r 处理时释放 char ptr？

 char *data = new char[temp->size()+1];//temp is of type string
 copy(temp->begin(),temp->end(),data);
 data[temp->size()]='\0';

 count = 0;

while(pointData != NULL)
{
if(count == 0)
pointData = strtok_r(data,":",&data);

else
pointData = strtok_r(NULL,":",&data);

if(count == 5)//some condition to free data
delete[] data;// this produces stack trace error

cout<<pointdata<<endl;

count++;
}

原文

When trying to delete/free character ptr without being processed completely by strtok_r, its giving me stack trace error.

I know that one cannot free/delete a strtok_r char ptr in a regular way, without completing the whole strings separation process by strtok_r func.

Can anyone tell me how to free a char ptr, when its under process by strtok_r?

 char *data = new char[temp->size()+1];//temp is of type string
 copy(temp->begin(),temp->end(),data);
 data[temp->size()]='\0';

 count = 0;

while(pointData != NULL)
{
if(count == 0)
pointData = strtok_r(data,":",&data);

else
pointData = strtok_r(NULL,":",&data);

if(count == 5)//some condition to free data
delete[] data;// this produces stack trace error

cout<<pointdata<<endl;

count++;
}

分享到QQ

分享到微博

如果你对这篇内容有疑问，欢迎到本站社区发帖提问参与讨论，获取更多帮助，或者扫码二维码加入 Web 技术交流群。

发布评论

需要登录才能够评论，你可以免费注册一个本站的账号。

不即不离 2025-01-11 07:03:04

因为 strtok_r 正在推进“数据”，这意味着它不再指向分配的地址；你需要保留一个“freedata”指针或类似的东西：

char *data, *freedata;

freedata = data = new char[temp->size()+1];

// do yer stuffz here

delete[] freedata;

Because strtok_r is advancing "data" as it goes, which means that it is no longer pointing at the address of the allocation; you need to keep a "freedata" pointer or the like around:

char *data, *freedata;

freedata = data = new char[temp->size()+1];

// do yer stuffz here

delete[] freedata;

回复收藏 0 原文

寂寞清仓 2025-01-11 07:03:04

在第三个参数中传递给 strtok_r 的上下文应该是指向要分隔的字符串的不同指针。尝试：

char *context;

....
pointData = strtok_r(data,":",&context);

else
pointData = strtok_r(NULL,":",&context);

我不认为您需要在传递它之前对其进行初始化。

The context passed to strtok_r in the third argument should be a different pointer to the string you want to separate. Try:

char *context;

....
pointData = strtok_r(data,":",&context);

else
pointData = strtok_r(NULL,":",&context);

I don't believe you need to initialise it before you pass it in.

回复收藏 0 原文

蓦然回首 2025-01-11 07:03:04

您可以永远传递给free的唯一指针是通过malloc获得的指针，或者从指定返回内存指针的函数获得的指针“就像”由 malloc 获得。 strtok_r 不会返回指向字符串的指针，“就像通过 malloc 获得的那样”，因此您不能对其调用 free。如果您阅读此函数的规范，它会返回一个指向输入字符串中字符的指针，该字符可能已被修改为使用空终止符破坏分隔符。