当存在视图控制器时，使用 ARC 的正确方法是什么？

发布于 2025-01-03 20:37:29 字数 410 浏览 2 评论 0原文

每次我展示我的新视图控制器（作为演示者 vc 中的属性）时，如下所示：

if(self.viewController) [self.viewController release];
self.viewController = [[ViewController alloc] init];
[self presentModalViewController:self.viewController animated:YES];

所以我总是保证获得一个新的对象实例（如果该对象已经存在）。

但现在我使用 ARC 并且不知道如何发送我的对象释放消息（因为不适用于 ARC）

你能帮我解决这个问题吗？

PS：每次我展示 gameVC 时，我都需要该对象的一个新实例。

谢谢大家！

原文

Every time I present my new viewcontroller (as property in presenter vc) as show below:

if(self.viewController) [self.viewController release];
self.viewController = [[ViewController alloc] init];
[self presentModalViewController:self.viewController animated:YES];

so I'm always guaranteed to get a new instance of object (if the object already exists).

But now I use ARC and don't have any ideas how to send my object release message (because is not work with ARC)

Can you help me with this issues?

PS: Every time when I present gameVC I need an new instance of the object.

Thanks all!

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圈圈圆圆圈圈 2025-01-10 20:37:29

self.viewController = [[ViewController alloc] init];
[self presentModalViewController:self.viewController animated:YES];

上面的代码将始终呈现一个新的 vc，苹果的编译器将负责发布。

但是如果你认为上面有一些问题（这是一个神话）那么你也可以这样做

self.viewController = nil;
self.viewController = [[ViewController alloc] init];
[self presentModalViewController:self.viewController animated:YES];

self.viewController = [[ViewController alloc] init];
[self presentModalViewController:self.viewController animated:YES];

the above code will always presents a new vc and apple's compiler will take care of the release.

But if you think the above have some problem(which is a myth) then you can do also like this

self.viewController = nil;
self.viewController = [[ViewController alloc] init];
[self presentModalViewController:self.viewController animated:YES];

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梦屿孤独相伴 2025-01-10 20:37:29

编译器为你放置了释放指令。您应该仅使用此代码并且它应该可以正常工作：

self.viewController = [[ViewController alloc] init];
[self presentModalViewController:self.viewController animated:YES];

The compiler puts the release instruction for you. You should use only this code and it should work OK:

self.viewController = [[ViewController alloc] init];
[self presentModalViewController:self.viewController animated:YES];

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南风几经秋 2025-01-10 20:37:29

您不应该持有指向视图控制器的指针。
我很确定你的代码应该如下所示：

ViewController *viewController = [[ViewController alloc] init];
[self presentModalViewController:viewController animated:YES];

You should not hold a pointer to your view controller.
I'm pretty sure your code should look like this:

ViewController *viewController = [[ViewController alloc] init];
[self presentModalViewController:viewController animated:YES];

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澜川若宁 2025-01-10 20:37:29

self.viewController = [[ViewController alloc] init];
[self presentModalViewController:self.viewController animated:YES];

是正确的方法。

但是，即使您使用手动引用计数，假设 viewController 是具有 retain 或 的 self 属性，此代码也是可以的>强标志。当你改变属性值时，之前的属性值会被释放，所以你不需要自己释放它。

self.viewController = [[ViewController alloc] init];
[self presentModalViewController:self.viewController animated:YES];

is the right way.

However, this code is OK even when you're using Manual Reference Counting, assuming that viewController is a property of self with retain or strong flag. When you're changing the property value, previous property value gets released, so you don't need to release it by yourself.

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