iOS - 比较 2 个数组和数组中的对象 - 逻辑问题

发布于 2025-01-03 16:08:38 字数 727 浏览 0 评论 0原文

我有一个包含 Person 对象的 NSArray 。

这个人对象包含以下内容；

> Name 
> Age 
> School 
> Address 
> Telephone_Number

稍后我将为此 person 对象设置值，例如 person.Name=@"Jemmy"; （但我不会设置其他属性，年龄，学校等）。

我有一个名为 personArray 的 NSArray，它包含 1000 条人员对象记录。现在我需要过滤掉包含 Name Jemmy 的所有对象。我该怎么做？

我想做的是；

NSMutableArray *arrayThatContainAllPersonObjects = [NSMutableArray arrayWithArray:personArray];
[arrayThatContainAllPersonObjects removeObjectsInArray:arrayWeAddedTheName];

但是，我将得到的是一个没有我的过滤结果的数组。无论如何，这可能不是正确的方法。我相信我们可以使用 NSSets、UNIONS 来解决这个问题。

注意：有些人可能会说这是一个重复的问题，但我对此进行了很多搜索。

原文

I have an NSArray which contains Person objects.

This person object contains the following;

> Name 
> Age 
> School 
> Address 
> Telephone_Number

Later on i will be setting values to this person object, like person.Name=@"Jemmy"; (but i will not be setting other attributes, Age, School etc.).

I have an NSArray called personArray, and it contains 1000 person object records in it. Now i need to Filter out all the objects that contains the Name Jemmy. How can i do this ?

What i was thinking of doing is;

NSMutableArray *arrayThatContainAllPersonObjects = [NSMutableArray arrayWithArray:personArray];
[arrayThatContainAllPersonObjects removeObjectsInArray:arrayWeAddedTheName];

But, what i will get is, an array that doesn't have my filter results. Anyway this might not be the correct approach. I believe we could use NSSets, UNIONS to solve this.

note:Some might say that this is a duplicate question, but i have searched so much on this.

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辞慾 2025-01-10 16:08:38

您希望将 NSPredicate 与 NSArray 的 filteredArrayUsingPredicate 一起使用。像这样的事情：

NSArray *filteredArray = [personArray filteredArrayUsingPredicate:[NSPredicate predicateWithFormat:@"name = \"Jemmy\""]];

You want to use an NSPredicate with NSArray's filteredArrayUsingPredicate. Something like this:

NSArray *filteredArray = [personArray filteredArrayUsingPredicate:[NSPredicate predicateWithFormat:@"name = \"Jemmy\""]];

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傾旎 2025-01-10 16:08:38

如果 Jemmy 都是相同的，那么简单的选择是

  NSArray * cleanArray = [arrayWithAll removeObjectIdenticalTo:jemmyPerson];

如果情况并非如此（他们被称为 Jemmy - 但有不同的学校或其他什么），那么您将陷入

   NSArray * cleanArray = [arrayWithAll filterUsingPredicate:jemmyPredicate];

或与块/迭代类似。谓词可以用以下内容构造：

   NSPredicate jemmyPredicate = [NSPredicate predicateWithFormat:@"name == \"jemmy\"];

或

    NSPredicate jemmyPredicate = [NSPredicate predicateWithBlock:^(id evaluatedObject, NSDictionary *bindings){
           return [evaluatedObject.Name isEqual:@"Jemmy"];
    }];

查阅谓词页面以获取更多详细信息。

If the Jemmy's are all identical the easy option is

  NSArray * cleanArray = [arrayWithAll removeObjectIdenticalTo:jemmyPerson];

If that is not the case (they are called Jemmy - but have different schools or whatever) you are down to

   NSArray * cleanArray = [arrayWithAll filterUsingPredicate:jemmyPredicate];

or similar with a block/iteration. The predicate can be constructed with something like:

   NSPredicate jemmyPredicate = [NSPredicate predicateWithFormat:@"name == \"jemmy\"];

    NSPredicate jemmyPredicate = [NSPredicate predicateWithBlock:^(id evaluatedObject, NSDictionary *bindings){
           return [evaluatedObject.Name isEqual:@"Jemmy"];
    }];

consult the predicate page for more details.

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