当字符串包含括号时如何配置正则表达式

发布于 2025-01-03 06:41:39 字数 404 浏览 1 评论 0原文

我确信这很简单，但我在网上找不到。

此代码：

    var new_html = "foo and bar(arg)";
    var bad_string = "bar(arg)";
    var regex = new RegExp(bad_string, "igm");
    var bad_start = new_html.search(regex);

将 bad_start 设置为 -1（未找到）。如果我删除 (arg)，它会按预期运行 (bad_start == 8)。我可以做些什么来使（非常方便的）“新正则表达式”语法起作用，还是我必须找到另一种方法？这个例子很简单，但在真正的应用程序中它将进行全局搜索和替换，所以我需要正则表达式和“g”。或者我也这样？

TIA

原文

I'm sure this is an easy one, but I can't find it on the net.

This code:

    var new_html = "foo and bar(arg)";
    var bad_string = "bar(arg)";
    var regex = new RegExp(bad_string, "igm");
    var bad_start = new_html.search(regex);

sets bad_start to -1 (not found). If I remove the (arg), it runs as expected (bad_start == 8). Is there something I can do to make the (very handy) "new Regexp" syntax work, or do I have to find another way? This example is trivial, but in the real app it would be doing global search and replace, so I need the regex and the "g". Or do I?

TIA

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失而复得 2025-01-10 06:41:39

通过双反斜杠 \\ 转义括号。试试这个。

    var new_html = "foo and bar(arg)";
    var bad_string = "bar\\(arg\\)";
    var regex = new RegExp(bad_string, "igm");
    var bad_start = new_html.search(regex);

演示

Escape the brackets by double back slashes \\. Try this.

    var new_html = "foo and bar(arg)";
    var bad_string = "bar\\(arg\\)";
    var regex = new RegExp(bad_string, "igm");
    var bad_start = new_html.search(regex);

Demo

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无悔心 2025-01-10 06:41:39

您需要转义要从中创建正则表达式的字符串中包含的特殊字符。例如，定义此函数：

function escapeRegex(string) {
  return string.replace(/[/\-\\^$*+?.()|[\]{}]/g, '\\amp;');
}

并使用它将结果分配给您的 bad_string 变量：

let bad_string = "bar(arg)"
bad_string = escapeRegex(bad_string)

// You can now use the string to create the Regex :v:

You need to escape the special characters contained in string you are creating your Regex from. For example, define this function:

function escapeRegex(string) {
  return string.replace(/[/\-\\^$*+?.()|[\]{}]/g, '\\amp;');
}

And use it to assign the result to your bad_string variable:

let bad_string = "bar(arg)"
bad_string = escapeRegex(bad_string)

// You can now use the string to create the Regex :v:

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℉絮湮 2025-01-10 06:41:39

您的正则表达式定义字符串应该是：

var bad_string = "bar\\(arg\\)";

使用正则表达式时需要对特殊字符进行转义，并且因为您在字符串中构建正则表达式，所以您需要对转义字符进行转义 :P

http://www.regular-expressions.info/characters.html

Your RegEx definition string should be:

var bad_string = "bar\\(arg\\)";

Special characters need to be escaped when using RegEx, and because you are building the RegEx in a string you need to escape your escape character :P

http://www.regular-expressions.info/characters.html

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